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Nat2105 [25]
3 years ago
15

5. Kendra is making a histogram for the data

Mathematics
1 answer:
valentinak56 [21]3 years ago
8 0

Answer:

The longest bar in her histogram is the Intervals 5-9 with the value of 5

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  Please have a look at the attached photo

My answer:

  • Intervals 0-4 : there are 2 results
  • Intervals 5-9 : there are 5 results
  • Intervals 10-14 : there are 4 results
  • Intervals 15-19 : there are 5 results

So the longest bar in her histogram is the Intervals 5-9 with the value of 5

Hope it will find you well.

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The area of a triangle is 54 cm2. The base is 18 cm. What is the height of the triangle? Let h represent the height of the trian
Margaret [11]

Hi,

h = 2 a/b so our answer would be 6. The height of the triangle is 6.

Have a great day!

7 0
3 years ago
Find the equation of the line<br><br> Y= __x + __
djyliett [7]

Answer:

y=2x+5

Step-by-step explanation:

0,5

0,7

7-5 is 2

2/0 is 2

to check answer:

(2*0)+5

0+5

=5

8 0
3 years ago
Read 2 more answers
Three friends go out for pizza. A slice costs $3.75 a soda costs $2.25. If they each get a soda and a total of 8 slices, how muc
Tpy6a [65]
Answer= 36.75
3.75x 8 = 30
2.25x3= 6.75
6.75+30=36.75
8 0
2 years ago
1 pts
balu736 [363]

9514 1404 393

Answer:

  $935.11

Step-by-step explanation:

The amount is given by the formula ...

  A = P(1 +r/n)^(nt) . . . P invested at rate r for t years compounded n per year

  A = $850(1 +0.024/2)^(2·4) = $935.11

The amount accumulated will be $935.11 after 4 years.

8 0
2 years ago
The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?
omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

T_5 = 160

T_7 = 40

Required

T_6

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

\frac{T_7}{T_5} = \frac{40}{160}

Divide the numerator and the denominator of the fraction by 40

\frac{T_7}{T_5} = \frac{1}{4} ----- equation 1

Recall that the formula of a GP is

T_n = a r^{n-1}

Where n is the nth term

So,

T_7 = a r^{6}

T_5 = a r^{4}

Substitute the above expression in equation 1

\frac{T_7}{T_5} = \frac{1}{4}  becomes

\frac{ar^6}{ar^4} = \frac{1}{4}

r^2 = \frac{1}{4}

Square root both sides

r = \sqrt{\frac{1}{4}}

r = ±\frac{1}{2}

Next, is to solve for the first term;

Using T_5 = a r^{4}

By substituting 160 for T5 and ±\frac{1}{2} for r;

We get

160 = a \frac{1}{2}^{4}

160 = a \frac{1}{16}

Multiply through by 16

16 * 160 = a \frac{1}{16} * 16

16 * 160 = a

2560 = a

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

T_n = a r^{n-1}

Here, n = 6;

T_6 = a r^{6-1}

T_6 = a r^5

T_6 = 2560 r^5

r = ±\frac{1}{2}

So,

T_6 = 2560( \frac{1}{2}^5) or T_6 = 2560( \frac{-1}{2}^5)

T_6 = 2560( \frac{1}{32}) or T_6 = 2560( \frac{-1}{32})

T_6 = 80 or T_6 = -80

T_6 =±80

Hence, the 6th term is positive/negative 80

8 0
3 years ago
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