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Mashutka [201]
3 years ago
8

Which of the following will NOT produce a triangle?

Mathematics
2 answers:
Phantasy [73]3 years ago
6 0
I think its d, because A and Cs angles make 180. And B has two equal sides that make it possible to make a triangle. Sorry i couldnt be more helpful
7nadin3 [17]3 years ago
6 0
D. Side Length of 4 in, 8 in and 12 in
This is because of a theorem(Theorem-
a statement that can be proven) called Triangle Side Theorem. In this statement, 2 side of a triangle has to be bigger than one side. In this problem 4+8=12 is not greater than 12. Therefore meaning D doesn’t produce a triangle.

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I need help with #3 plz
Nadusha1986 [10]
The correct answer is A. 10 bracelets

5 0
3 years ago
Read 2 more answers
A family paid $26.400 as a down payment for a home. If this represents 16% of the price of the home, find the price of the home.
Vlada [557]
The correct answer is:

How to find X if P percent of it is Y. Use the percentage formula Y/P% = X

Convert the problem to an equation using the percentage formula: Y/P% = X
Y is 26,400, P% is 16%, so the equation is 26,400/16% = X
Convert the percentage to a decimal by dividing by 100.
Converting 16% to a decimal: 16/100 = 0.16
Substitute 0.16 for 16% in the equation: 26,400/0.16 = X
Do the math: 26,400/0.16 = X
X = 165,000
So $ 165,000 is the price of the home.

I hope this helps you!!
7 0
3 years ago
Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
Im cond=fused on it and really need help to continue<br> to pass my classes
maxonik [38]

Answer:

http://www.calcul.com/show/calculator/recurring-decimal-to-fraction?i=0.02...

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A.Calculate the mean,median and mode.(3 points each) 1.)1,2,3,4,5 2.)2,3,4,5,6,6 3.)6,7,5,4,5,6,2,5
zlopas [31]

Answer:

Step-by-step explanation:

1.)1,2,3,4,5

mean=sum of all values/number of values

         =1+2+3+4+5/5

         =15/5

mean=3

Mode :

In the given data, no observation occurs more than once.

Hence the mode of the observations does not exist, means mode=0.

Median

1,2,3,4,5

Middle value is 3 so the median is 3.

2.)2,3,4,5,6,6

mean=sum of all values/number of values

         =2+3+4+5+6+6/6

         =26/6

mean =4.33

Mode

      is that value of the observation which occurs maximum number of times so here mode is 6.

Median

2,3,4,5,6,6

 4+5/2

9/2

median=4.5

3.)6,7,5,4,5,6,2,5

mean=sum of all values/number of values

         =6+7+5+4+5+6+2+5/8

        =40/8

mean =5

Mode

is that value of the observation which occurs maximum number of times so here mode is 5

Median

2,4,5,5,5,6,6,7

5+5/2

10/2

median=5

 

5 0
3 years ago
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