All categories

3 years ago

How do you solve this

Mathematics

2 answers:

evablogger [386]3 years ago

7 0

Multiply 5 and 9 which is 45.

dedylja [7]3 years ago

3 0

V = 45
9x5 = 45
45/5 = 9

You might be interested in

In the figure, PQ is parallel to RS. The legth of RP is 4 cm; the length of PT is 16 cm; the length of QT is 20 cm. What is the

Studentka2010 [4]

4/16 = SQ/20

SQ = (4*20) / 16 = 5 cm

6 0

3 years ago

Read 2 more answers

I need it to be in least to greatest

Reil [10]

-28, -17, 22.4, |-27|

3 0

3 years ago

Read 2 more answers

Hannah purchased three items at the store for $7.05, $8.12, and $3.97. She paid for

vichka [17]

Answer:

She should receive $30.86

Step-by-step explanation:

$7.05 + $8.12 + $3.97 =19.14

50 - 19.14 = 30.86

6 0

3 years ago

Rewrite the following expression as the sum if two addends. -0.03 - 1.809

kumpel [21]

The answer is -1.839

6 0

3 years ago

Skipping Lunch A nutritionist wishes to determine, within 3%, the true proportion of adults who do not eat any lunch. If he wish

mixas84 [53]

Answer:

A sample of at least 545 adults is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$\pi = 0.15$

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

If he wishes to be 95% confident that his estimate contains the population proportion, how large a sample will be necessary?

We need a sample of at least n.

n is found when M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.15*0.85}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.15*0.85}$

$\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.03}$

$(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.03})^{2}$

$n = 544.23$

Rounding up

A sample of at least 545 adults is needed.

6 0

3 years ago