Answer:
please find attached pdf
Step-by-step explanation:
29 and 3
13 and 19
Hope this helps!
Answer:
the area of the hexagon is approx. 187.1 in²
Step-by-step explanation:
Picture this regular polygon as being a hexagon made up of six equilateral triangles of side 12 in. We find the area of one such triangle and then multiply that by 6 to obtain the total area of the hexagon.
One such equilateral triangle has three sides all of length 12 in, and all the interior angles are 60°. The height of one such triangle is
h = (12 in)sin 60°, or
√3
h = (12 in) -------- = 6√3 in
2
So, with base 12 in and height 6√3 in, the area of one such equilateral triangle is
A = (1/2)(12 in)(6√3 in) = 36√3 in²
and the total area of the hexagon is 6(36)√3 in², or approx. 187.1 in²
Using the law of cosine:
Cosine(angle) = Adjacent leg / Hypotenuse
You are given the angle, and the adjacent leg and need to solve for X, which is the hypotenuse.
Using the formula above you have:
Cosine(58) = 17 / x
Solve for x by dividing 17 by cos(58)
x = 17 / cos(58)
x = 32.08