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Blizzard [7]
3 years ago
14

Solve -3(-2x+20)=-8(x+12)+92 please?

Mathematics
1 answer:
sveta [45]3 years ago
8 0
The answer is x=4 hope it helps
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What is the length of the diameter of a circle inscribed in a right triangle with the length of hypotenuse c and the sum of the
jeyben [28]

Answer:

  diameter = m - c

Step-by-step explanation:

In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).

The sum of the lengths of the tangents from points A and B on side "c" is ...

  (b-r) +(a-r) = c

  (a+b) -2r = c

Now, the problem statement defines the sum of side lengths as ...

  a+b = m

and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...

  m -d = c

  m - c = d . . . . add d-c

The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.

5 0
3 years ago
I NEED HELP IM BEGGING YOU????:) Write the slope-intercept form of the equation for the line.
iogann1982 [59]
It’s d because the slope is negative and it is 2/1 which can also be written as just 2. in the formula y=mx+b, m is the slope and b is the y-intercept. the y-intercept is where the line touches the y axis(in this case -1) so it would be written as y=2x+(-1)
8 0
3 years ago
Whoever gets this correct gets brain, 5 stars and a thanks! An explanation of it would be amazing! Tysm!
ivanzaharov [21]
For d and e are correct
I really hope this helps! Have an awesome day:D
3 0
3 years ago
Read 2 more answers
Please help with any question !! need help
Gre4nikov [31]

Answer:

1/ 4/5

2/ 6/8 = 3/4

3/ 4/5

4/ 4/10 = 2/5

5/ 2/4 = 1/2

4 0
3 years ago
Can someone please help me with this problem?
omeli [17]
I think is the one on the top left but not really sure, and wish you luck with that lesson.
5 0
4 years ago
Read 2 more answers
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