(x,y)
x=input
y=output
example
we see
g=(1,2)
theefor
g(1)=2

a.
f(4)=1
g(1)=2
g(f(4))=2

b.
g(-2)=4
f(4)=1
f(g(-2))=1

c.
f(3)=5
g(5)=5
f(5)=0
f(g(f(3)))=0

5 0

3 years ago

2. Use the distributive property to rewrite the following expression.<br> 3(x+5)

baherus [9]

The answer is 3x+15

You multiply the x and 5 by 3 to get 3x and 15

6 0

3 years ago

The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago

Plz help me plz help me

sladkih [1.3K]

Answer:

In one hour Stephanie earns $1.50 more than Marco

Step-by-step explanation:

w=9h

H is a variable

9×hour= wage

9×15= $135

9×18= $162

157.50-135=$22.50

189-162=$27

27-22.50=4.50

Now cause its per hour we know she earns $4.50 more in 3 hours.

4.50÷3=$1.50

8 0

2 years ago