Remaining water in the tank is (19/2-19/3) gallons = 57-38/6=19/6 =3 1/6 gallons
The equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5 is 
<em><u>Solution:</u></em>
<em><u>The slope intercept form is given as:</u></em>
y = mx + c ----- eqn 1
Where "m" is the slope of line and "c" is the y - intercept
Given that the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5
Given line is perpendicular to − 4 x − 3 y = − 5
− 4 x − 3 y = − 5
-3y = 4x - 5
3y = -4x + 5

On comparing the above equation with eqn 1, we get,

We know that product of slope of a line and slope of line perpendicular to it is -1

Given point is (-1, -2)
Now we have to find the equation of line passing through (-1, -2) with slope 
Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1



Thus the required equation of line is found
Answer: She had left 54% of the money which is $1620.
Step-by-step explanation:
40% of $3000 = $1200
15% of $1200 = $180
$3000 - ($1200 + $180)
$3000 - $1380 = $1620
$1620 is the money she had left.
$1620 is 54% of $3000
She had 54% left of the money.
Hope that helped~!
Answer:
x= - 1/35. I'm pretty sure this is right.
Answer:
37° and 53° respectively.
Step-by-step explanation:
We need to know that the angles are complementtary if ∠RSU + ∠UST = 90°. Then,
5x+7 + 9x-1 = 90
5x + 9x +7 -1 = 90
14x +6 = 90
14x = 90 - 6
14x = 84
x = 84/14
x = 6.
Then, the angle ∠RSU has measure 5(6)+ 7 = 30+7 = 37, and the angle ∠UST has measure 9(6) - 1 = 54-1 = 53.