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kotegsom [21]
3 years ago
6

The radius of a cylindrical construction pipe is 2.5 ft. If the pipe is 28 ft long, what is its volume?

Mathematics
2 answers:
atroni [7]3 years ago
8 0

Answer:

V = 549.5 ft³

Step-by-step explanation:

The formula for the volume, V, of a cylinder of radius r and length h is

V = πr²h.

Substituting 2.5 ft for r and 28 ft for h, we get the volume

V = 3.14(2.5 ft)²(28 ft), or

V = 549.5 ft³

Margarita [4]3 years ago
7 0

Answer:

V = 550 ft^3

Step-by-step explanation:

The volume of a cylinder is

V = pi r^2 h

We know the radius is 2.5 and the height is 28

V = 3.14 * (2.5)^2 * 28

V =549.5 ft^3

Rounding to the nearest whole number

V = 550 ft^3

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