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kotegsom [21]
3 years ago
6

The radius of a cylindrical construction pipe is 2.5 ft. If the pipe is 28 ft long, what is its volume?

Mathematics
2 answers:
atroni [7]3 years ago
8 0

Answer:

V = 549.5 ft³

Step-by-step explanation:

The formula for the volume, V, of a cylinder of radius r and length h is

V = πr²h.

Substituting 2.5 ft for r and 28 ft for h, we get the volume

V = 3.14(2.5 ft)²(28 ft), or

V = 549.5 ft³

Margarita [4]3 years ago
7 0

Answer:

V = 550 ft^3

Step-by-step explanation:

The volume of a cylinder is

V = pi r^2 h

We know the radius is 2.5 and the height is 28

V = 3.14 * (2.5)^2 * 28

V =549.5 ft^3

Rounding to the nearest whole number

V = 550 ft^3

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Thomas deposited $800 into two different accounts.
Mazyrski [523]
I’d go with D, you do 350 and multiply it by 0.0425 and do the same with 450 and multiply by 0.0425 and you multiply each of those answers and then add them to 800
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2 years ago
Karen will divide her garden into equal parts. She will plant corn in 8/12 of the garden. What is the lowest number of parts she
Ronch [10]

Answer:

  3 parts

Step-by-step explanation:

8/12 = 2/3

Apparently, Karen wants to divide her garden into 3 parts and plant 2 of them in corn.

5 0
3 years ago
State whether each sequence is arithmetic and justify your answer. If the sequence is arithmetic, write a recursive and an expli
nasty-shy [4]

Answer:

Part A

f(n)=52-12(n-1)

f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.

Part B

(2,4,8,16,32)\: \: Geometric Sequence

Part C

1/4,3/4,5/4,7/4,9/4

g(n)=\frac{1}{4}+\frac{2}{4}(n-1)\\f(n)=\left\{\begin{matrix}1/4if \: \:n=1 & \\ f(n+1)+2/4& if\: n\geq 2 \end{matrix}\right

Part D:

h(n)=1.1+0.4(n-1)\\h(n)=\left\{\begin{matrix}1.1 & if\:n=1 \\ h(n+1)+0.4 & if\:n\geq 2\end{matrix}\right

Step-by-step explanation:

By definition, an Arithmetic Sequence holds the same difference between each following number.

Part A

(52,40, 28, 16)\\52-40=12\\40-28=12\\28-16=12\\d=12

<u>Explicit Formula</u>

To write an explicit formula is to write it as function.

f(n)=52-12(n-1)

<u>Recursive Formula</u>

To write it as recursive formula, is to write it as recurrence given to some restrictions:

f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.

Part B

(2,4,8,16,32)\: \:

Geometric Sequence, since 2*2=4 8*2=16 and 16*2=32 and 8+2=10 8+16=24

Part C

(\frac{1}{4},\frac{3}{4},\frac{5}{4},\frac{7}{4},\frac{9}{4})\\\

Arithmetic Sequence, difference

d=\frac{2}{4}

<u>Explicit Formula:</u>

g(n)=\frac{1}{4}+\frac{2}{4}(n-1)

<u>Recursive Formula</u>

g(n)=\left\{\begin{matrix}\frac{1}{4} &if\:n=1 \\ g(n+1)+\frac{2}{4} &if\: n\geq 2\end{matrix}\right.

Part D

(1.1,1.5,1.9,2.3,2.7) Arithmetic Sequence, difference d=0.4

<u>Explicit formula</u>

h(n)=1.1+0.4(n-1)\\

<u>Recursive Formula</u>

h(n)=\left\{\begin{matrix}1.1 &if\:n=1 \\ h(n+1)+0.4 &if\: n\geq 2\end{matrix}\right.

6 0
3 years ago
Penelope made note of all the bicycles and cars she could see parked or locked on acertain city block. All the cars had exactly
lesantik [10]

Given:

The number of cycles is, <em>n</em> (s) = 7.

The number of wheels in the cycle is, <em>n </em>(sw) = 2.

The number of cars is, <em>n</em> (c) = 15.

The number of wheels in the car is, <em>n</em> (cw) = 4.

The obective is to find the total number of wheels.

The total number of wheels is,

\begin{gathered} T=n(sw)\cdot n(s)+n(cw)\cdot n(c) \\ =2\cdot7+4\cdot15 \\ =14+60 \\ =74\text{ whe}els \end{gathered}

Hence, there are 74 wheels in the block.

If there are <em>x</em> bicycles and <em>y </em>cars, the equatioin will be,

\begin{gathered} T=n(sw)\cdot x+n(ce)\cdot15 \\ T=2x+4x \end{gathered}

Hence, the number of wheels for x bicycles and y cars is 2x+4x.

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ELEN [110]

Answer: 13.85kg Hope this helps, please consider making me Brainliest.

Step-by-step explanation:

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7 + 6 + .25 + .6 = 13 + .85 =

13.85

8 0
1 year ago
Read 2 more answers
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