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lord [1]
3 years ago
12

Can the numbers 24, 32, 40 be the lengths of the three sides of a right triangle? Explain why or why not.

Mathematics
2 answers:
andre [41]3 years ago
7 0

Answer:

no, because two sides have to be equal

Step-by-step explanation:

Anna007 [38]3 years ago
5 0

Answer:

24, 32, 40 can be the lengths of the three sides of a right triangle

Step-by-step explanation:

Pythagoras theorem:

c^2 = a^2 + b^2

40^2 = 1,600

32^2 + 24^2 = 1024 + 576 = 1,600

If the square of the length of the hypotenuse (longest side length)  is equal to the sum of the squares of the lengths of the other two sides then it's a right triangle

So

40^2 = 32^2 + 24^2

1,600 = 1,600

24, 32, 40 can be the lengths of the three sides of a right triangle

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the fee for the parking garage at the airport is $16 for the first day plus $4.50 for each additional day. which equation repres
11111nata11111 [884]
It will be a. f=4.5d+16. Unlike the other equations. F represents the fee for the parking garage, and d represents the number of days. 
6 0
3 years ago
5x+20y=4<br> x=-4y+1<br><br> Solve for x/y
Andrews [41]

Hi there!


Looks like a lot of work is going on here.


Let's start by solving this equation for the x.


5x + 20y = 4


Step 1) Add -20y to both sides.


5x + 20y + - 20y = 4 - 20y 5x = -20y + 4


Step 2) Divide both sides by 5.


\frac{5x}{5}  = \frac{-20y + 4}{5}


x = -4y +  \frac{4}{5}


Final Answer:


x = -4y +  \frac{4}{5}


Now, let's solve for y.


Step 1) Add -5x to both sides.


5x + 20y + - 5x = 4 + - 5x 20y = -5x + 4


Step 2) Divide both sides by 20.


\frac{20y}{20} =  \frac{-5x + 4}{20}


y =  \frac{-1}{4} x +  \frac{1}{5}


Final Answer:


y =  \frac{-1}{4} x +  \frac{1}{5}


Hope this helps! :D


Hint - When you have two variables in an equation, and you want to solve for one, the other will end up in your answer. :)

6 0
3 years ago
Please show working out thanks
IgorLugansk [536]

Answer:

10m x 15m

Step-by-step explanation:

You are given some information.

1. The area of the garden: A₁ = 150m²

2. The area of the path: A₂ = 186m²

3. The width of the path: 3m

If the garden has width w and length l, the area of the garden is:

(1) A₁ = l * w

The area of the path is given by:

(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36

Multiplying (2) with l gives:

(3) A₂l = 6l² + 6lw + 36l

Replacing l*w in (3) with A₁ from (1):

(4) A₂l = 6l² + 6A₁ + 36l

Combining:

(5) 6l² + (36 - A₂)l +6A₁ = 0

Simplifying:

(6) l² - 25l + 150 = 0

This equation can be factored:

(7) (l - 10)*(l - 15) = 0

Solving for l we get 2 solutions:

l₁ = 10, l₂ = 15

Using (1) to find w:

w₁ = 15, w₂ = 10

The two solutions are equivalent. The garden has dimensions 10m and 15m.

3 0
3 years ago
Rewrite the expression in a radical form z^1/6
mylen [45]

Answer:

\sqrt[6]{z}

Step-by-step explanation:

The denominator of the fractional exponent is the index of the root.

7 0
3 years ago
What shape is created by a cross-section of a triangular prism cut perpendicular to the bases?
Butoxors [25]

Answer:

Its a triangle .And the question says triangular

7 0
3 years ago
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