Which ones are NOT a function? 20 POINTS!!!!

Molly has nine blue beads eight red beads and seven green beads. She wants to share the beads equally with six friends. How many

Schach [20]

Answer:

1 1/2 blue beads 1.3 red beads and 1.2 green beads

Step-by-step explanation:

8 0

3 years ago

Can someone solve this for me with their explanation please?

Lana71 [14]

First you want to subtract 36

so it looks like this $\sqrt[4] {(4x+164)^3}=64$

Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)

${(4x+164)^3}=64^4$ which is equal to ${(4x+164)^3}=16777216$

Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]

Then you end up with the equation 4x+164=256

Then subtract 164 to both sides

4x=92

then divide 92 by 4

Then you get x=23

7 0

4 years ago

What is 7 divided by 2 4/5

Nutka1998 [239]

It should be 0.4 or 4/10 or 2/5

8 0

3 years ago

Read 2 more answers

Forty square inches of material is available to make a cylindrical; can of tuna and water. What dimensions of the can will give

krek1111 [17]

The dimensions of the can are 1.457 inches and 2.913 inches that will give the most volume

Step-by-step explanation:

Let us revise the rule of surface area and volume of a cylinder

S.A = 2π r h + 2π r²
V = π r² h

Forty square inches of material is available to make a cylindrical; can of tuna and water, we need to find the dimensions of the can that will give the most volume

∵ S.A = 40 inches²

∵ S.A = 2π r h + 2π r²

∴ 2π r h + 2π r² = 40

Let us use this rule to find h in terms of r

- Subtract 2π r² from both sides

∵ 2π r h = 40 - 2 π r²

- Divide both sides by 2π r

∴ $h=\frac{40-2\pi r^{2}}{2\pi r}$

∴ $h=\frac{40}{2\pi r}-\frac{2\pi r^{2}}{2\pi r}$

∴ $h=\frac{20}{\pi r}-r$

∵ V = π r² h

- Substitute h by its value above

∴ $V=\pi r^{2}(\frac{20}{\pi r}-r)$

∴ V = 20 r - π r³

To find the most volume differentiate it with respect to r and equate it by 0 to find the value of r

∵ $\frac{dV}{dr}$ = 20 - 3π r²

∵ $\frac{dV}{dr}$ = 0

∴ 20 - 3π r² = 0

- Add 3π r² to both sides

∴ 20 = 3π r²

- Divide both sides by 3π

∴ r² = 2.122

- Take √ for both sides

∴ r = 1.457 inches

To find h substitute the value of r in the expression of h

∵ $h=\frac{20}{\pi r}-r$

∴ $h=\frac{20}{\pi (1.457)}-(1.457)$

∴ h = 2.913 inches

The dimensions of the can are 1.457 inches and 2.913 inches that will give the most volume

Learn more:

You can learn more about volume of solids in brainly.com/question/6443737

#LearnwithBrainly

3 0

4 years ago

There are two traffic lights on the route used by a certain individual to go from home to work. Let E denote the event that the

uranmaximum [27]

Answer with Step-by-step explanation:

We are given that

E=Event denote the event that the individual must stop at the first light

F=Event denote the event that the individual must stop at the second light

P(E)=0.4

P(F)=0.2

$P(E\cap F)=0.15$

a.We have to find the probability that the individual must stop at atleast one light.

We know that

$P(E\cup F)=P(E)+P(F)-P(E\cap F)$

Substitute the value in the given formula then, we get

$P(E\cup F)=0.4+0.2-0.15=0.45$

$P(E\cup F)=0.45$

b. $P(E\cup F)'=1-P(E\cup F)$

$P(E\cup F)'=1-0.45=0.55$

c.We have to find the probability that the individual must stop at exactly one of the two lights.

P(must stop at exactly one of the two lights)= $P(E\cup F)-P(E\cap F)=0.45-0.15=0.3$

P(must stop at exactly one of the two lights)=0.3

d.We have to find the probability that the individual must stop just at the first light.

P(must stop juts at the first light)= $P(E)-P(E\cap F)$

P(must stop juts at the first light)=0.4-0.15=0.25

8 0

3 years ago