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3 years ago

Can someone solve this for me with their explanation please?

Mathematics

1 answer:

Lana71 [14]3 years ago

7 0

First you want to subtract 36

so it looks like this $\sqrt[4] {(4x+164)^3}=64$

Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)

${(4x+164)^3}=64^4$ which is equal to ${(4x+164)^3}=16777216$

Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]

Then you end up with the equation 4x+164=256

Then subtract 164 to both sides

4x=92

then divide 92 by 4

Then you get x=23

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Geoffrey wants to make one planter that extends from the ground to just below his back window. The window starts 3 feet off the

sweet [91]

Answer:

Explained

Step-by-step explanation:

the volume of the planter needs to be 36 cubic feet

height can be 3 feet and not more

therefore are the product of its length and breadth = 36/3 = 12 ft

l×b= 12

there land be can be any two multiples of 12

1 and 12, 3 and 4 , 6 and 2 are possible values of length and breath.

7 0

3 years ago

find the interest earned on an account with $450 principal, and interest rate of 6% over a period of 8 years

puteri [66]

8
450(1+.06) = 717.23

4 0

3 years ago

Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu

vitfil [10]

Answer:

a) The minimum head breadth that will fit the clientele = 4.105 inches to 3d.p = 4.1 inches to 1 d.p

b) The maximum head breadth that will fit the clientele = 8.905 inches to 3 d.p = 8.9 inches to 1 d.p

Step-by-step explanation:

This is normal distribution problem.

A normal distribution has all the data points symmetrically distributed around the mean in a bell shape.

For this question, mean = xbar = 6.1 inches

Standard deviation = σ = 1 inch

And we want to find the lowermost 2.3% and uppermost 2.3% of the data distribution.

The minimum head breadth that will fit the clientele has a z-score with probability of 2.3% = 0.023

Let that z-score be z'

That is, P(z ≤ z') = 0.023

Using the table to obtain the value of z'

z' = - 1.995

P(z ≤ - 1.995) = 0.023

But z-score is for any value, x, is that value minus the mean then divided by the standard deviation.

z' = (x - xbar)/σ

- 1.995 = (x - 6.1)/1

x = -1.995 + 6.1 = 4.105 inches

The maximum head breadth that will fit the clientele has a z-score with probability of 2.3% also = 0.023

Let that z-score be z''

That is, P(z ≥ z'') = 0.023

Using the table to obtain the value of z''

P(z ≥ z") = P(z ≤ -z")

- z'' = - 1.995

z" = 1.995

P(z ≥ 1.995) = 0.023

But z-score is for any value, x, is that value minus the mean then divided by the standard deviation.

z'' = (x - xbar)/σ

1.995 = (x - 6.1)/1

x = 1.995 + 6.1 = 8.905 inches

6 0

3 years ago

a satellite's escape velocity is 6.5 mi/sec, the radius of the earth is 3960 mi, and the earth's gravitational constant is 32.2

Artyom0805 [142]

Answer:

$23.89x10^{6}$ ft

Step-by-step explanation:

$\frac{V^{2} }{R^{2} } = \frac{2g}{R+h} \\$ This is the formula to find satellite's escape velocity V , where R is earth's radius, h is the satellite's height from the earth surface and g is the earth's gravitational constant.

$R^{2}(R+h) \frac{V^{2} }{R^{2} } =R^{2} (R+h)\frac{2g}{R+h}$ (Multiplying to clear the fractions)

(R+h) $V^{2} =R^{2} 2g$

$R+h=\frac{2R^{2}g }{V^{2} }$

$h= \frac{2R^{2} g}{V^{2} } -R$

Now, we can determine height of satellite from the surface of the earth

by putting the values in above equation

$h= \frac{2 * (3960)^{2}*32.2 }{6.5^{2} } -3960\\h= 23.902 x10^{6} - 3960\\ h=23.89x10^{6} ft$

5 0

2 years ago

the ratio of the length of an airplane wing to its width is 6 to1 . if the length of a wing is 12.5 meters ,how wide must it be

erastova [34]

If you set up a proportion, this will make sense.

$\frac{6}{1}= \frac{12.5}{x}$

Now, Cross Multiply

6x = 12.5

x = 25/12

3 0

3 years ago