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sladkih [1.3K]
3 years ago
6

Can someone solve this for me with their explanation please?

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0

First you want to subtract 36

so it looks like this \sqrt[4] {(4x+164)^3}=64

Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)

{(4x+164)^3}=64^4 which is equal to {(4x+164)^3}=16777216

Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]

Then you end up with the equation 4x+164=256

Then subtract 164 to both sides

4x=92

then divide 92 by 4

Then you get x=23




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Explain please thanks :)
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Answer:

24

Step-by-step explanation:

The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.

Okay, on to the problem:

We can do one digit at a time.

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There are 4 digits that we can choose from. (3, 4, 6, and 7)

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No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.

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Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.

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