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zavuch27 [327]
3 years ago
8

What is the simplified expression for 5 to the power of negative 3 multiplied by 2 to the power of 2 multiplied by 5 to the powe

r of 6 whole over 2 to the power of 3 multiplied by 5 to the power of 2?
2 to the power of 2 over 5 to the power of 2
5 over 2 to the power of 2
5 over 2
5 to the power of 2 over 2
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0
The answer is 1562.5 I think.
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Approximate √12 to the nearest tenth.
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√12 in nearest tenth is 3.5 is the answer

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Tizah wants to put a fence around her garden. she has 22 yards of fence material. Does she gave enough to go all the way around
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4 years ago
The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d
EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.

It is provided that X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2}).

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})

                   =P(Z>1)\\\\=1-P(Z

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

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3 years ago
Which construction would you use to construct a right triangle with a compass and a straightedge?
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A I think would be the correct answer

5 0
3 years ago
1 Solve the compound inequality 4x&gt;-16 or 6x &lt;-48<br>​
Yuliya22 [10]

Answer:

Step-by-step explanation:

4x > -16 reduces to x > -4:  All numbers greater than x = -4 (shaded area to the right of -4).

6x < -48 reduces to x < -8:  All numbers to the left of -8 (shaded area to the left of -8).

Solution:  (-infinity, -4) ∪ (-8, infinity)

The number line between -8 and -4 is not part of the solution set (is not shaded or darkened)

Draw an open circle at -8 and extend an arrow to the left of this circle.  Then draw an open circle at -4 and extend an arrow to the right of this circle.

5 0
3 years ago
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