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astraxan [27]
2 years ago
5

What is the value of x?

Mathematics
1 answer:
Ksenya-84 [330]2 years ago
5 0

Answer:

20

Step-by-step explanation:

2x - 5 = x + 15

2x - x = 5 + 15

x = 20

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-np-4≤2(c-3)
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HELP PLEASE ILL GIVE BRAINLIEST
iren [92.7K]

The surface of the triangle count formula

A = b*h*1/2

A - area

b - base

c - height

The 1st triangle

A₁ = b₁*h = 6in * 8in *1/2= 24in²


The 2nd triangle

A₂ b₂*h = 10in * 8in*1/2 = 40in²


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3 0
3 years ago
The radius of a CD is 6cm which equation could be used to find the circumference of the CD in cm ?
9966 [12]

Answer:

2πr

Step-by-step explanation:

to find the circumference you must multiply the radius by pi and 2

5 0
2 years ago
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Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}  (1)

furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

5 0
3 years ago
Read 2 more answers
564 which statement is false? It is the sum of 56 tens and 4 ones. The number of hundreds is more than the number of tens. To ge
nirvana33 [79]

Answer:

The number of hundreds is more than the number of tens.

Step-by-step explanation:

The sum of 56 tens and 4 ones= 560 + 4 (true)

The number of hundreds is more than the number of tens.

Number of hundreds = 5

Number of tens = 56

5 is not greater than 56.

7 0
3 years ago
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