If you keep getting money he wont catch up, but if not he'll get $7.14 a day up to $100. He will be pass you so you will take out some days so you both are at $75 on the 4 day of the next day you guys will be close he will have $78.56.
<span> D Q</span>
TC<span> = D x P <span>+ ___ x Cp + ____ x
Cs</span></span>
<span>Q 2</span>
TC: Total Cost
P: Price per unit
Q: Quantity
Cp: Cost of issuance of a purchase order
<span>Cs: storage cost per unit</span>
After the construction of a circle, we have to "Set the compass to the radius of the circle" so, option C is correct.
<h3>What is a regular hexagon?</h3>
A regular hexagon is defined as a closed shape consisting of six equal sides and six equal angles. The sum of the measure of angles of a regular hexagon is 120 degrees.
Steps to create an inscribed hexagon:
1: The structure needs to adjust the box thickness towards that radius.
2: Afterward moves around the outside of the circular path to just produce the 6 vertices of that similar hexagon.
"Set the compass to the radius of the circle" so, option C is correct.
Thus the above answer is correct.
Learn more about inscribed hexagons here:
brainly.com/question/21502832
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Let X be the number of burglaries in a week. X follows Poisson distribution with mean of 1.9
We have to find the probability that in a randomly selected week the number of burglaries is at least three.
P(X ≥ 3 ) = P(X =3) + P(X=4) + P(X=5) + ........
= 1 - P(X < 3)
= 1 - [ P(X=2) + P(X=1) + P(X=0)]
The Poisson probability at X=k is given by
P(X=k) = 
Using this formula probability of X=2,1,0 with mean = 1.9 is
P(X=2) = 
P(X=2) = 
P(X=2) = 0.2698
P(X=1) = 
P(X=1) = 
P(X=1) = 0.2841
P(X=0) = 
P(X=0) = 
P(X=0) = 0.1495
The probability that at least three will become
P(X ≥ 3 ) = 1 - [ P(X=2) + P(X=1) + P(X=0)]
= 1 - [0.2698 + 0.2841 + 0.1495]
= 1 - 0.7034
P(X ≥ 3 ) = 0.2966
The probability that in a randomly selected week the number of burglaries is at least three is 0.2966
Answer and Step-by-step explanation:
× 12 can also be written as
because the 12 is multiplying the numerator of the fraction.
12 can also be written as
.
When we solve, this is what is happening:
× 
The 12 will be multiplying the 2, while the 1 will be multiplying the 3. Because 3 times 1 is 3, we don't show the 1. So, that can leave us with 2 being multiplied by 12 in the numerator.
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