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Alla [95]
3 years ago
9

Before a race, Evelyn ran 27 minutes to warm up. The race took her 2 hours.

Mathematics
1 answer:
Gwar [14]3 years ago
4 0

Answer:

C. 147 minutes

Step-by-step explanation:

This is 147 minutes because 2 hours equal up to 120 minutes, before that Evelyn ran 27 minutes. So, now you have to add 120 and 27. You get 147.

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If the original price of dima’s skirt was $54, how much more could she have saved at the store her friend suggested?
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$1.80


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Becky says that lines c and d are parallel.
katen-ka-za [31]

A) angle 1 = angle 2 - Incorrect

These angles are only on one of the following lines, which means that they do not show that lines C and D are parallel. In addition, angles 1 and 2 are supplementary, so they could not be equal.

B) angle 1 + angle 2 = 180 - Incorrect

Though this is true, this does not prove that lines C and D are parallel because both of these angles are on the same line.

C) angle 2 = angle 3 - Correct

These angles are alternate interior angles and there are angles on both lines, which proves that lines C and D are parallel.

D) angle 2 + angle 3 = 180 - Incorrect

These angles are equivalent, so they cannot add up to 180 degrees unless the intersecting line was perpendicular to both lines C and D.

Hope this helps!! :)

5 0
3 years ago
67min; 1.1h. Which one is more precise
Brums [2.3K]

Answer:

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Step-by-step explanation:

8 0
2 years ago
Find all the zeros of f(x) help please
Licemer1 [7]

Since f(6)=0, by the remainder theorem this means that <em>x</em> - 6 divides <em>f(x)</em> exactly. This means there are constants <em>a</em>, <em>b</em>, and <em>c</em> such that

\dfrac{f(x)}{x-6} = ax^2 + bx + c

Multiplying both sides by <em>x</em> - 6 gives

f(x) = (x-6)(ax^2+bx+c) \\\\ 2x^3-19x^2+45x-18 = ax^3 + (b-6a)x^2 + (c-6b)x - 6c

Then <em>a</em>, <em>b</em>, <em>c</em> satisfy

\begin{cases}a=2 \\ b-6a=-19 \\ c-6b=45 \\ -6c=-18\end{cases}

and solving this system gives <em>a</em> = 2, <em>b</em> = -7, and <em>c</em> = 3.

So, we have

2x^3-19x^2+45x-18 = (x - 6) (2x^2 - 7x + 3)

The quadratic term can be factored as

2x^2 - 7x + 3 = (2x - 1)(x - 3)

which leaves us with

f(x) = (x-6)(2x-1)(x-3)

so that the zeros of <em>f(x)</em> are 6, 1/2, and 3.

4 0
3 years ago
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