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Lana71 [14]
3 years ago
11

(4.76) × (12.5) simplified

Mathematics
2 answers:
densk [106]3 years ago
6 0

Answer:

I believe the answer is 59.5.

Step-by-step explanation:

If I understood this problem correctly, you'd have to multiply 4.76 times 12.5. As an answer, I got 59.5.

dsp733 years ago
4 0

Answer:

59.5

Step-by-step explanation:


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2 3/5 * 3 1/3<br> Just answer please
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Answer: 8.66666666667

Step-by-step explanation:

3 0
3 years ago
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3a−15=4a−3a I NEED HELP WITH THIS ASAP PLZ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
GaryK [48]

Answer:

a = 15/2

Step-by-step explanation:

3a−15=4a−3a

Combine like terms

3a - 15 = a

Subtract 3a from each side

3a-3a−15=a−3a

-15 = -2a

Divide each side by -2

-15/-2 = -2a/-2

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3 years ago
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Which ordered pairs could be points on a line parallel to the line that contains (3,4) and (-2,2) check all that apply.
bogdanovich [222]

Answer:

B: (-1, 1) and (-6, -1)

D: (1, 0) and (6, 2)

E: (3, 0) and (8, 2)

Step-by-step explanation:

Hope this helps! :D

4 0
3 years ago
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El área de un mosaico es de 900cm2 ¿cuánto mide por lado cada mosaico​
olga2289 [7]

Answer:

El lado de cada mosaico tiene una longitud de 30 cm.

Step-by-step explanation:

El area de un mosaico cuadrado es:

A=l^{2}

Donde l es el lado del mosaico.

Entonces, si sabes que el area es 900 cm², el lado valdra:

900=l^{2}

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6 0
3 years ago
(8CQ) Determine whether the series -5+25-125+... is convergent or divergent.
Aloiza [94]

Answer:

The answer is divergent ⇒ answer (b)

Step-by-step explanation:

* The series is -5 + 25 + -125 + ........

- It is a geometric series with:

- first term <em>a</em> = -5 and common ratio <em>r</em> = 25/-5 = -5

* The difference between the convergent and divergent

  in the geometric series is :

- If the geometric series is given by  sum  = a + a r + a r² + a r³ + ...

* Where <em>a</em> is the first term and <em>r</em> is the common ratio

* If |r| < 1 then the following geometric series converges to a / (1 - r).  

- Where a/1 - r is the sum to infinity

* The proof is:

∵ S = a(1 - r^n)/(1 - r) ⇒ when IrI < 1 and n very large number

∴ r^n approach to zero

∴ S = a(1 - 0)/(1 - r) = a/(1 - r)

∴ S∞ = a/1 - r

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∴ IrI = 5

∴ IrI > 1

∴ The series is divergent

5 0
3 years ago
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