X = string section
y = brass section
x = y + 35
y = 29 .....there are 29 in the brass section
x = 29 + 35
x = 64...there are 64 in the string section
for a total of : 64 + 29 = 93 total musicians <==
a.129.6+16.2
= 145.8
b.129.6×16.2
= 2099.52
c.129.6÷16.2
= 8
d.129.6−16.2
= 113.4
e.192.4+14.8
= 207.2
Becasue the data may be skewed right or left (not symmetrical)
that is obvious when the median lean to left or right while the maximum and minimum records are still as they are.
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Answer:
There can be at most 
attendees in a corporate team-building event.
Step-by-step explanation:
Let 
denotes number of attendees in a corporate team-building event.
Fixed cost = $19
Cost charged per attendee = $1
Budget for the corporate team-building event = $31
Therefore,
So, there can be at most attendees in a corporate team-building event.
I believe this answer is greater than
