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3 years ago

Factor completely 3x^2+2x-1

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

4 0

Answer:

(3x - 1)(x + 1)

Step-by-step explanation:

3x^2 factors into 3x and x.

-1 factors into -1 and 1.

Now we try different positions of 3x, x, -1, and 1 until we find the correct factorization.

Try: (3x - 1)(x + 1)

When you multiply the two factors together, the middle term will be 3x - x = 2x

Since 2x is the original middle term, this is the correct factorization.

Answer: (3x - 1)(x + 1)

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In a local town, 4/5 of the voting-age population is registered to vote. If 7/8 of the registered voters voted in the election

STALIN [3.7K]

Answer:

$\frac{7}{10}$ of voting age population voted

Step-by-step explanation:

In order to find out that fraction we just have to mulitply the fraction of the people that were registered by the fractions of the people that were registered and voted. And so we get...

$(\frac{4}{5})(\frac{7}{8}) = \frac{(4)(7)}{(5)(8)} = \frac{28}{40} = \frac{7}{10}$

7 0

2 years ago

Help help help thanks

Dmitry [639]

Answer: a=2/5b + 1/5c (I may have answered your question but idk if I did)

Step 1: Add -4a to both sides.

9a−2b+−4a=4a+c+−4a

5a−2b=c

Step 2: Add 2b to both sides.

5a−2b+2b=c+2b

5a=2b+c

Step 3: Divide both sides by 5.

5a/5=2b+c/5

a=2/5b+1/5c

7 0

3 years ago

Will Mark branliest! :)<br><br> (At the end it says round the the nearest tenth) thank you!

Jobisdone [24]

Answer:

Step-by-step explanation:

20 x 15 is 450 and add it to the semi circle which us 88.4

Hope this helps u :D

3 0

2 years ago

Read 2 more answers

How do I divide integers with different signs

jek_recluse [69]

Multiply or divide normally. Whenever the signs are different it’s always gonna be a negative.

7 0

3 years ago

Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

5 0

3 years ago