Question

You are making cookies for a party. The ratio of Cookie Tray A to Cookie Tray B to Cookie Tray C is 2 : 3 : 4. If you need to make a total of 171 trays, how many of each tray will there be? If each Tray has 20 cookies, how many cookies will you need to make Tray A? Tray B? Tray C?

Answer 1

Given that the ratio of three trays is A : B : C = 2 : 3 : 4

Let us consider the common factor among the number of trays be "x".

If we need to make a total of 171 trays, then the equation of sum of trays would be :-

Type A + Type B + Type C = 171

2x + 3x + 4x = 171

9x = 171

x = $\frac{171}{9}$ = 19

So we have following number of trays :-

Number of type A trays = 2x = 38 trays.

Number of type B trays = 3x = 57 trays.

Number of type C trays = 4x = 76 trays.

Now if each tray contains 20 cookies, then we would have following arrangements :-

Cookies in type A trays = 38×20 = 760 cookies.

Cookies in type B trays = 57×20 = 1140 cookies.

Cookies in type C trays = 76×20 = 1520 cookies.