If y is proportional to x and y = -15 when x = -20, what is the value of x when y = 12?

2 answers:

7 0

Maybe i have that you wanted We can represent the situation like that: Y=-15 and x=-20 Then When y=12 x=? We make x(The unknown) *-15=12*(-20) We have an simple équation to solve Thus x=(12*(-20))/-15 X=16

givi [52]3 years ago

5 0

X1= -20
x2= x2
y1= -15
y2= 12

x1 : x2 :: y1 : y2
-20 : x :: -15: 12

Means = x and -15
Extremes= -20 and 12

<span>Product of mean = Product of extremes
</span> -15x = -20*12
x = -240/-15
x2 = 16

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Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

GuDViN [60]

Answer:

Euler's method is a numerical method used in calculus to approximate a particular solution of a differential equation. As a numerical method, we have to apply the same procedure many times, until get the desired result.

In first place, we need to know all the values the problem is giving:

The step size is 0.2; h = 0.2. This step size is a periodical increase of the x-variable, which will allow us to calculate each y-value to each x.
The problem is asking the solution y(1), which means that we have to find the y-value assigned for x = 1, through the numerical method.
The initial condition is y(0) = 9. In other words, $x_{o} = 0\\y_{0}=9$ .

So, if the initial x-value is 0, and the step size is 0.2, the following x-value would be: $x_{1}=0.2$ ; then $x_{2}=0.4$ ; $x_{3} =0.6; x_{4} =0.8;x_{5} =1$ ; and so on.