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2 years ago

What is the perimeter of the quadrilateral that is the length of 7 height of 8

Mathematics

2 answers:

scoray [572]2 years ago

7 0

Answer:

<h2>30 units</h2>

Step-by-step explanation:

assuming it is a rectangle, there is no information on the shape of the quadrilateral, add all sides.

7 + 8 + 7 + 8 = 30 units

marta [7]2 years ago

6 0

Answer:

Step-by-step explanation:

What you need to do is add all the sides when you want to find perimeter so for this one you would want to do 8+8+7+7 and that should give you 30. I hope I could help!!

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PLease hep me Im in a huge rush

Ratling [72]

X=52 (vertically opposite angles)

6 0

3 years ago

Read 2 more answers

An artificial soccer pitch is 91 meters long and 43 meters wide. If the cost of the pitch is AED 20 per square meter. What is th

Novosadov [1.4K]

The Cost of installing the artificial soccer pitch is $5360

A rectangle is a quadrilateral (has four sides and four angles) in which opposite sides are parallel and equal.

The soccer pitch us rectangle in shape. Hence:

Perimeter of soccer pitch = 2(length + width) = 2(91 + 43) = 268 meters

Cost of installing the pitch = $20 per meter * 268 meters = $5360

The Cost of installing the artificial soccer pitch is $5360

Find out more on perimeter at: brainly.com/question/16596982

6 0

2 years ago

What integer describes a decrease of seven? (A. 7 / B. -7 / C. 0 / D. 1/7)

Pie

Answer:

I thin B -7 cause its negative and negative goes down.

Step-by-step explanation:

3 0

3 years ago

A) 2 x -7 = b) -3 x 4 = c) -5 % -6 =

erastovalidia [21]

Answer:

a)2×-7= -14

b)-3×4= -12

c)-5%+6= -6.05

8 0

3 years ago

Read 2 more answers

If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle

stira [4]

Answer:

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

Step-by-step explanation:

Given points end Points are p(-3,-2) and q( 1,6)

The distance of two points formula

P Q = $\sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2} }$

P Q = $\sqrt{1 - (-3)^{2} + ((6 -(-2))^{2} }$

P Q = $\sqrt{16+64} = \sqrt{80}$

The diameter 'd' = 2 r

2 r = √80

= $\sqrt{16 X 5}$

= $4 \sqrt{5}$

r = 2√5

Mid-point of two end points

$(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )$

= (-1 ,2)

Mid-point of two end points = center of the circle

(h,k) = (-1 , 2)

The equation of the circle

(x -h )² +(y-k)² = r²

(x -(-1) )² +(y-(2))² = (2(√5))²

x² + 2 x + 1 + y² - 4 y + 4 = 20

x² + 2 x + y² - 4 y = 20 -5

x² + 2 x + y² - 4 y = 15

Final answer:-

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

6 0

3 years ago