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BartSMP [9]
3 years ago
11

5/2 as a division problem

Mathematics
1 answer:
svetoff [14.1K]3 years ago
8 0

Answer: 2.5

Step-by-step explanation:

You have the following fraction given in the problem above:

5/2

Where the number on the top is called the numerator and the number on the bottom is called denominator.

To solve this exercise you must divide the numerator 5 by the denominator 2.

Therefore, you obtain the folloowing result:

5/2=2.5

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The price of meal at a restaurant is 200% more than the 100$, it was a couple of decades ago. What is the price now?
netineya [11]

Answer:

The price now is 300$.

Step-by-step explanation:

The problem is related to percentages.

It is provided that the price of meal at a restaurant a couple of decades (20 years) ago was 100$.

Now the price is 200% more than what it was 20 years ago,i.e. the price increased by 200%.

Compute the new price as follows:

New-Price=100\$+[100\$\times200\%]\\= 100\$+[100\times\frac{200}{100}]\$\\ =100\$+200\$\\=300\$

Thus, the price of the meal now is 300$.

7 0
3 years ago
a map has a scale of 3cm : 18 km. If riverside & Smithville are 54 km apart they are how far apart on the map?
Finger [1]
Alright! To solve this one you first have to find out what 1cm is equal to in km, to do that you have to divide 18km by 3cm:

[18 ÷ 3] = 6.

Now we know that 1cm is 6km. To find how far apart they are on the map you simply divide 54km by 6km:

[54 ÷ 6] = 9.

They are 9cm apart on the map.
3 0
3 years ago
I need help with this ASAP
Tasya [4]

Answer:

hope this will help you........

3 0
2 years ago
Read 2 more answers
Which of the following g expressions is equal to 3x^2+27
Dafna1 [17]

Answer:

Answer is 3(x^2 + 9), when factored.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What's the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m
storchak [24]
Given:
height = 6m
chord = 20 m

We need to find the radius of the circle.

20 m = 2 √ [ 6m( 2 x radius - 6 m ) ] 
20 m / 2 = 2 √<span>[ 6m( 2 x radius - 6 m ) ] / 2 </span>
10 m = √<span> [ 6m( 2 x radius - 6 m ) ] </span>
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ² 
100 m²<span> = 6 m( 2 x radius - 6 m ) </span>
100 m²<span> = 12 m x radius - 36 sq m </span>
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m² 
136 m²<span> = 12 m x radius </span>
136 m²<span> / 12 m = 12 m x radius / 12 m </span>
<span>11.333 m = radius 
</span>
the area beneath an arc: 

<span>Area = r</span>²<span> x arc cosine [ ( r - h ) / r ] - ( r - h ) x </span>√<span>( 2 x r x h - h</span>²<span> ).
</span>
<span>r</span>²<span> = (11.333 m)</span>²<span> = 128.444 m</span>²<span> </span>
<span>r - h= 11.333 m - 6 m = 5.333 m </span>
<span>r * h = 11.333 m x 6 m = 68 m</span>²

<span>Area = 128.444 m</span>²<span> x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x </span>√<span>[ 2 x 68 m</span>²<span> - 36 m</span>²<span> ] </span>

<span>Area = 128.444 m</span>²<span> x arc cosine [ 0.4706 ] - 5.333 m x </span>√<span> [ 100m</span>²<span> ] </span>

<span>Area = 128.444 m</span>²<span> x 1.0808 radians - 5.333 m x 10 m </span>

<span>Area = 138.828 m</span>²<span> - 53.333 m</span>²<span> </span>

<span>Area = 85.4 m</span>²
6 0
4 years ago
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