Answer:
n to the power of -2
Step-by-step explanation:
i counted all the others and this is the only one that doesn't add up to 16. the last answer is -16 not 16 so there you go.
Well, luckily it is apparent that (x-1) is a root because when x=1 the equation is equal to zero. So we can divide the equation by that factor to find the other roots.
(2x^3+9x^2+4x-15)/(x-1)
2x^2 r 11x^2+4x-15
11x r 15x-15
15 r 0
(x-1)(2x^2+11x+15)=0
(x-1)(2x^2+6x+5x+15)=0
(x-1)(2x(x+3)+5(x+3))=0
(x-1)(2x+5)(x+3)=0
So the roots are x= -3, -2.5, 1
This is my first time on this app but this question doesn’t look to hard i’m ok at math but not that good at showing my work
Isosceles triangles have to equal sides
and each side is 5 cm greater than the base
you know the perimeter is 46
i would use basic algebra
x = base
46 = 2(x +5) + x
the 2(x +5) is the equal sides
46 = 2(x+5) + x
using distributive property
46 = 2x + 10 + x
add the common variable
46 = 3x + 10
now it’s easy
3x = 46 - 10
3x = 36
x = 36 / 3
x = 12
now that we got x (base)
we know that the equal sides are 5 cm longer than the base
12 + 5 = 17
since there are 2 sides and they are equal they are both 17
so each side of the triangle would be
1. 17 cm
2. 17 cm
3. 12 cm
to check you should be able to add them all together and get 46
17 + 17 + 12 = 46
Answer:
Assuming the area is made up of a square and a semicircle.
<u>Perimeter</u>
The side length of the square = 18 ft
We can see 3 full side lengths plus one side length from which we need to subtract 12 ft (see attached diagram).
⇒ perimeter of the square = (3 x 18) + (18 - 12)
= 54 + 6
= 60 ft
Circumference of a circle = 
d (where d is the diameter)
⇒ arc length of the semicircle = 1/2 circumference
= 1/2 · · 12
= 6 ft
Total perimeter = 60 + 6 = 78.8 ft (nearest tenth)
<u>Area</u>
Area of a square = s² (where s is the side length)
⇒ area of square = 18²
= 324 ft²
Diameter = 2r ⇒ r = 1/2 diameter
Area of a circle = r² (where r is the radius)
⇒ area of the semicircle = 1/2 · · 6²
= 18 ft²
Total area = 324 + 18 = 380.5 ft² (nearest tenth)
