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igomit [66]
3 years ago
8

I rly need help pls help me

Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0
<span>x = 11/cos24</span>° 
   = 11/0.9135
   = 12.0  to the nearest tenth. 
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17. Only tenth-, eleventh-, and twelfth-grade students
Tom [10]

Answer: Eleventh Grade

Step-by-step

The ratio of tenth graders to the school's total population is 86:255 = 33.7%.

The ratio of eleventh graders to the school's total population is 18:51 = 35.3%.

Since the probability of a student being in either tenth, eleventh, or twelfth grade = 1 = 100% (that is, certainty), then the probability of a randomly drawn student being in twelfth grade is (100-33.7-35.3)% = 31.0%.

When randomly choosing one student from the whole school, it is most likely (35.3%) that the student is in the eleventh grade.

4 0
4 years ago
(WILL GIVE BRAINLIEST) Solve for x.
Oksanka [162]

Answer:

−2(−9x+5)−4x=2(x−5)−4

Step 1: Simplify both sides of the equation.

−2(−9x+5)−4x=2(x−5)−4

(−2)(−9x)+(−2)(5)+−4x=(2)(x)+(2)(−5)+−4(Distribute)

18x+−10+−4x=2x+−10+−4

(18x+−4x)+(−10)=(2x)+(−10+−4)(Combine Like Terms)

14x+−10=2x+−14

14x−10=2x−14

Step 2: Subtract 2x from both sides.

14x−10−2x=2x−14−2x

12x−10=−14

Step 3: Add 10 to both sides.

12x−10+10=−14+10

12x=−4

Step 4: Divide both sides by 12.

12x

12

=

−4

12

x= -1/3

Step-by-step explanation:

Good luck! Hope this helps! <3

3 0
3 years ago
Read 2 more answers
Evaluate.<br><br> 10^2 + 6 ⋅ 7 + 8<br><br> A. 70<br><br> B. 142<br><br> C. 150<br><br> D. 190
Kaylis [27]
I hope this helps you




100+42+8



100+50


150
8 0
3 years ago
Solve for x<br> Enter the solutions from least to greatest.<br> -4x^2– 7 = -11
Pavlova-9 [17]

Answer:

x = 1, x = -1

Step-by-step explanation:

-4x² = -4

x² = 1

x = \sqrt{1}

x = ±1

3 0
3 years ago
Is 2,12 4,24 6,36 8,48 10,60 proportional
Elena L [17]

Answer:

Yes

Step-by-step explanation:

12 divided by 2 = 6, 24 divided by 4 = 6, 36 divded by 6 = 6, 48 divded by 8 = 6, 60 divided by 10 = 6.  

All answers have 6 so yes it is proportional.

4 0
3 years ago
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