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SVETLANKA909090 [29]

3 years ago

5

Can someone please help me with this?

1 answer:

Anettt [7]3 years ago

7 0

Answersorry

Step-by-step explanation:sorry idk

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What value is added to both sides of the equation x2 - 8x = -10 in order to solve by completing the square?

IgorLugansk [536]

X² - 8x = -10

to have a complete square, we must have this format:

a² + 2ab + b²

a² = x²
2ab = -8x ⇒ 2(x)(-4)
b² = -4² = 16

x² - 8x + 16 = -10 + 16
x² - 8x + 16 = +6
(x-4)² - 6 = 0

Both sides must have an additional value of 16.

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3 years ago

If arc AXC = 235°, what is m∠ABC?<br><br> 117.5°<br> 60°<br> 55°<br> 125°

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3 years ago

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Kala found an icicle 26 inches long. How long is it in feet?

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About 2 feet and 2 inches

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Tamara spun the arrow on a spinner 50 times. The number of times the arrow landed on each colored section of the spinner is show

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Answer: 1/2 or 23/50

Step-by-step explanation:

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3 years ago

1) Graph the following lines and using the graph determine several values of x for which the graph is positive (negative):

Aleksandr [31]

1) $y=-0.5x-2$

The graph of the above equation is attached in the attachment below.

For all the values from negative infinity to -4, the function is positive.

X ∈ (-∞,-4]

2) $y=-1.5x+3$

To find the x- intercept, plug y =0

$0=-1.5x+3$

$1.5x=3$

$x=2$

x intercept = (2,0)

To find the y- intercept, plug x=0

$y=-1.5(0)+3$

$y=3$

Y- intercept = ( 0,3)

3) $y=13-x$

Y- intercept = (0,13)

x- intercept = (13,0)

Area of triangle = $\frac{bh}{2}$

Area of triangle = $\frac{13\times13}{2}$

Area = $\frac{169}{2}$ sq unit.

4) The graphs of $y=-2x+7$ and $y=0.5x-5.5$ is attached in the attachment below.

The intersection point is ( 5,-3)

5) A = (-3,0)

B = (4,5)

C = (0,-4)

Slope of AB = $\frac{5-0)}{4-(-3)} =\frac{5}{7}$

Slope intercept of line $y=mx+b$

Where, m is the slope and b is the y- intercept.

Plugging point A and the slope in the y- intercept to find the value of b.

$0=\frac{5(-3)}{7} +b$

$b=\frac{15}{7}$

Equation of line AB: $y=\frac{5x}{7} +\frac{15}{7}$

Slope of BC = $\frac{-4-5}{0-4} =\frac{9}{4}$

Plug C = (0,-4)

$-4=0+b$

b=-4

equation of line BC= $y=\frac{9x}{4} -4$

Slope of line AC = $\frac{-4-0}{0--3} =\frac{-4}{3}$

Equation of line AC = $y=\frac{-4x}{3} -4$

Y intercept of AB = $(0,\frac{15}{7} )$

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3 years ago

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