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tamaranim1 [39]
3 years ago
13

How do you find a frequency of a class when the relative frequency is given

Mathematics
1 answer:
ryzh [129]3 years ago
6 0

Step-by-step explanation:

Remember, you count frequencies. To find the relative frequency, divide the frequency by the total number of data values. To find the cumulative relative frequency, add all of the previous relative frequencies to the relative frequency for the current row.

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A box with a height (x+5) has a square base with side x. A second box with height (x+2) has a square base with side (x+5). If th
sergeinik [125]

Answer :

x = -1.43

Explanation :

As given ,

The first box has a height (x+5) has a square base with side x

So, the Length and Breadth of the box are x and x respectively.

Now,

The volume of first box = Length×Breadth×Height

                                       = (x).(x).(x+5)

                                       = x²(x+5)

⇒The volume of first box = x²(x+5)

Now,

Given that , the second box with height (x+2) has a square base with side (x+5).

So, the Length and Breadth of the box are (x+5) and (x+5) respectively.

Now,

The volume of second box = Length×Breadth×Height

                                             =  (x+5). (x+5).(x+2)

                                              = (x+5)²(x+2)

⇒The volume of second box =  (x+5)²(x+2)

Now,

Given that,  the two boxes have the same volume

⇒x²(x+5) =  (x+5)²(x+2)

⇒x² =  (x+5)(x+2)

⇒x² =  x² + 2x + 5x + 10

⇒x² - x² =  7x + 10

⇒0 =  7x + 10

⇒ 7x = -10

⇒ x = -\frac{10}{7} = -1.43

⇒ x = -1.43

As volume of first box = x²(x+5) = (-1.43)²(-1.43+5) = 7.30 ≈ 7

As volume of second box =  (x+5)²(x+2) = (-1.43+5)²(-1.43+2) = 7.26 ≈ 7

At x = -1.43, Volume of both the boxes are same.

4 0
2 years ago
Find the number of terms in this series: 3x + 5x + 7x + ... + 23x
bogdanovich [222]
3x 5x 7x 9x 11x 13x 15x 17x 19x 21x 23x
5 0
1 year ago
Evaluate: (x^2-1)/(x-1) if x goes to 1?
egoroff_w [7]

Step-by-step explanation:

\displaystyle \lim_{x \to 1} \dfrac{(x^2 - 1)}{(x-1)} = \lim_{x \to 1} \dfrac{(x - 1)(x+1)}{(x-1)}

\:\:\:\:\:\:\:\:\displaystyle = \lim_{x \to 1} (x+1) =2

6 0
3 years ago
Help this is due today!
Luda [366]

Answer:

A

Step-by-step explanation:

Automatically if you use the intercept (where it cuts the line) which would be 3.

8 0
3 years ago
Rainfall decreased by 0.166. this year. Express this decimal as a percent?
Anettt [7]
0.166 as a percent is 16.6%!

I hope this helped. :)

Please give me brainliest if I am correct! 
7 0
3 years ago
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