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solniwko [45]
3 years ago
11

I nreed help aspa plzzzzzzzzz

Mathematics
1 answer:
Llana [10]3 years ago
7 0
ᗯITᕼ ᗯᕼᗩT 234567889666$OK
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A pharmacist receives a special request from an ophthalmologist to prepare a fortified tobramycin ophthalmic solution.
Harrizon [31]

Answer:

2/7 ml

Step-by-step explanation:

When we have a solution expressed in Q mg/ml, the concentration is (Q/10)%.

For example, a solution of 3 mg/ml is a 3/10=0.3% concentration solution, a solution of 40 mg/ml is a 40/10=4% concentration solution.

<em>Why? </em>

Q mg/ml means that 1 ml of solution has Q mg of the drug or active component. So, 100 ml have 100*Q mg.

But 100*Q mg = Q/10 grams.

If a solution has Q/10 grams in 100 ml, then it is a (Q/10)% concentration.

Now, we have 5 ml of a solution that contains tobramycin, 3 mg/ml (each ml has 3 mg of tobramycin).

This means that the 5 ml contain 15 mg of  tobramycin.

On the other hand, we have another solution S containing 40 mg/ml of tobramycin. This means that each ml of S contains 40 mg of tobramycin.

Let x be the amount of ml of S we have to add to our first 5 ml.

If 1 ml of S contains 40 mg of  tobramycin, x ml contain 40*x mg.

If we add this x ml to our first 5 ml, we have 5+x ml containing 15+40*x mg of  tobramycin.  

Now, cross-multiply to get how much tobramycin contains 1 ml of this new solution.

5+x ml ____contain____15+40*x mg of  tobramycin

   1 ml ____contains____? mg

And we have

\large \frac{5+x}{1}=\frac{15+40x}{?}\Rightarrow ?=\frac{15+40x}{5+x}

as a result, we have a solution of  

\large \frac{15+40x}{5+x}\;mg/ml

We want to prepare a solution 0.5% in concentration.

Using what we state at the beginning, we need to find a value x such that

\large \frac{(15+40x)/(5+x)}{10}=0.5

solving for x

\large \frac{(15+40x)/(5+x)}{10}=0.5\Rightarrow \frac{15+40x}{5+x}=5\Rightarrow 15+40x=25+5x\Rightarrow\\\\\Rightarrow 40x-5x=25-15\Rightarrow 35x=10\Rightarrow x=10/35=2/7 \;ml

So, we have to add just 2/7 ml of the stronger solution.

6 0
3 years ago
Julio and Jake start their reading assignments the same day. Jake is reading a 152−page-book at a rate of 18 pages per day. Juli
Sergeeva-Olga [200]
Jake= 18 x 7
Jake= 126

Julio= 18(1.5) x 7
Julio= 27 x 7
Julio= 189

Jake= 152 - 126 = 26
Julio= 210 - 189 = 21
26 - 21 = 5

After 7 days, Jake will have 5 more pages left to read than Julio.
7 0
3 years ago
Please help thanks so much!
ZanzabumX [31]
1 is A
2 is A
when you solve 5x + 3 = 58 you get x = 11 an 5x + 3 < 58 snce 8<11
7 0
4 years ago
Kevin and monica lead visitor tours at a museum. Last month, both kevin and monica led the same number of vistors. Kevin lead 15
kiruha [24]

Answer:

Number of students in each group = 8

Step-by-step explanation:

kevin and monica led the same number of vistors.

Let x = number of students in each group

Kevin lead 150 adults, plus 6 student groups.

150 + 6x

Monica led 134 adults, plus 8 student groups.

134 + 8x

Equate both equations

150 + 6x = 134 + 8x

Collect like terms

150 - 134 = 8x - 6x

16 = 2x

Divide both sides by 2

x = 16 / 2

= 8

x = 8

Number of students in each group = 8

3 0
3 years ago
Y = - 2/3x + 2 in standard form
Lesechka [4]

Answer:

2x + 3y = 6

Step-by-step explanation:

2x + 3y = 6

-2x. -2x

3y/3 = -2x + 6/3

Y = -2/3x + 2

4 0
3 years ago
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