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Kazeer [188]
3 years ago
12

Q: Angelica uses the point (4,3) to represent the location of her house and uses the point (10,8) to represent the location of a

gas station. Each unit on the graph represents 1 mi. How far is the gas station from Angelica's house? Show your work.
Mathematics
2 answers:
oksian1 [2.3K]3 years ago
4 0

Answer:

The answer to your question is 7.8 mi

Step-by-step explanation:

Data

H (4,3)

G (10, 8)

Process

1.- Use the distance between to points formula to find the distance

        dHG = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}

x1 = 4       y1 = 3

x2 = 10    y2 = 8

2.- Substitution

         dHG = \sqrt{(10 - 4)^{2} + (8 - 3)^{2}}

3.- Simplification

         dHG = \sqrt{6^{2} + 5^{2}}

         dHG = \sqrt{36 + 25}

         dHG = \sqrt{61}

4.- Result

         dHG = 7.8 mi

xenn [34]3 years ago
4 0

Answer:

I agree with the first response. They deserve to get the Brainliest

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What is the slope of a line passing through (3, 4) and (5, 8)?<br> 4/2 2/4 1/2 or 2
ollegr [7]

Answer:

Step-by-step explanation:

(3,4)=x1,y1 (5,8)=x2,y2. The slope is calculated using formula: Slope =y2−y1x2−x1. =8−45−3. =42. =2.

3 0
3 years ago
3. What are the factors of<br> 9x2 - 30x + 25?
vaieri [72.5K]

{(3x)}^{2}-2(3x)(5)+{5}^{2}

−2(3x)(5)+5

2

{(3x-5)}^{2}

4 0
3 years ago
I will give brainliest fast please I will give points please explain well
ANEK [815]

If the equal is 55x + 35y = 200

x: time-driven at 55 miles/hour

y: time-driven at 35 miles/hour

If the car spends 2.5 hours at 35 miles per hour, then it drove:

 55x + 35(2.5) = 200

    55x =35

       y = 112.5

There the drive spent about 2.5-hour driving at 55 mph.

Hope it helps!

4 0
2 years ago
Acellus. please help me
Doss [256]

by-step explaAnswer:

by-step epla

Step-nation:

a

6 0
3 years ago
20 points if you help me solved this problem plz it’s urgent someone plz help me I need help! Will mark you as brainiest!
deff fn [24]

Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

   x = 1.0, C(x) = 39

   x = 1.1,  C(x) = 63

   x = 2.5, C(x) = 87

   x = 3.0, C(x) = 87

   x = 4.8, C(x) = 135

   x = 5.0, C(x) = 135

   x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

3 0
3 years ago
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