Answer:
$460.38
Step-by-step explanation:
Use the exponential decay formula, y = C(1 - r)^t
Plug in the original price, depreciation rate, and amount of time:
y = 20000(0.875)^11
y = 460.38
So, the car's value after 11 years will be $460.38
Answer:
220.67 pounds
Step-by-step explanation:
This problem can be treated as a compounded interest with a weekly rate of -1%. Cal's weight after 'n' weeks at a 1% loss rate per week is described by the following expression:
For n = 10 weeks, Cal's weight is:
He expects to weigh 220.67 pounds at the end of the ten weeks.
1st statement
Justin has 7.5 more than Eva 7.5+E
Eva = E
2nd statement
Emma has 12 less than Justin J - 12
when J= Justin = 7.5 + E
last statement
Eva+Justin+Emma = 63
E + (7.5+E) + (7.5+E-12) =63
ADD UP
3E + 15 - 12 = 63
3E + 3 = 63
3E=63 - 3
3E=60
E=20 EMMA receives 20
J=7.5+20
J=27.5 JUSTIN receives 27.5
M=J-12
M=27.5-12
M=15.5 EMMA receives 15.5
(-7, 2) is the location of W.
because W on the X axis is -7
and W on the Y axis is 2.
making it (-7, 2)
