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ra1l [238]
3 years ago
10

Supervisor: "Because you are working a late shift, you will get an increase in your wage. You will get an additional 10% per hou

r from 6:00 PM to 12:00 AM and additional 15% from 12:00 AM to 1:00 AM." Employee: "I am working from 2:00 PM to 12:00 AM. Between 2:00 PM and 6:00 PM, I will make $12.00 per hour. Between 6:00 PM and 12:00 AM, I will make __________ per hour."
Mathematics
1 answer:
rewona [7]3 years ago
7 0

Answer:

I will make <u>$ 13.20</u> per hour

Step-by-step explanation:

Given:

Employee gets money for Working from 2.00 PM to 6.00 PM = \$ 12 per hour

Employee gets money for working from 6.00 PM to 12.00 AM  will get additional 10\%=\frac{10}{100}\times12= \$ 1.2 per hour

Employee gets money for working from 12.00 AM to 01.00 AM will get additional 15\%=\frac{15}{100}\times12= \$ 1.8 per hour

Solution:

Employee works from 2.00 PM to 12.00 AM= Employee gets money for Working from 2.00 PM to 6.00 PM + 10\% extra wage = \$ 12 + \$ 1.2 = \$ 13.2

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Nookie1986 [14]

Answer:

Error is in between the second and third step

the exponents must be subtracted

Step-by-step explanation:

8 0
2 years ago
Plssssssss help........
Ludmilka [50]

the answer to ur problem will be -7/5

7 0
3 years ago
Read 2 more answers
Lines and triangles practices
Marianna [84]
<1 = 123
60 + 63 = 123
180 - 123 = 57
180 n- 57 = 123

Triangle angle-sum theorem
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idk what the last one is about sorry

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4 0
3 years ago
A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions
salantis [7]

Dimensions are length 20 meter and width 14 meter

<em><u>Solution:</u></em>

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

<em><u>A rectangle has width that is 6 meters less than the length</u></em>

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

<em><u>The area of the rectangle is given by formula:</u></em>

Area = length \times width

<em><u>Substituting the values we get,</u></em>

Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0

<em><u>Solve the above equation by quadratic formula</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}

a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14

Since, length cannot be negative, ignore a = -14

<em><u>Thus solution of length is a = 20</u></em>

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0
3 years ago
What is the completely factored form of x3-64?
nataly862011 [7]
<span>a^3 - b^3 = (a - b) </span><span>(<span>a^2 + </span>ab + b^2)
</span><span>so
x^3 - 4^3 = (x - 4)(x^2 + 4x + 16)

hope it helps</span>
7 0
3 years ago
Read 2 more answers
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