What is the perimeter to the nearest 10th of a unit

Mathematics

1 answer:

Viktor [21]3 years ago

6 0

Remember that perimeter is the sum of the lengths of the sides. The way to find the length of the sides is $\sqrt{ ( x_{2} - x_{1} )^{2} * ( y_{2} - y_{1} )^{2} }$ where $(x_{1},y_{1})$ is one endpoint of one line, while $(x_{2},y_{2})$ is the other endpoint of the same line. Repeat this formula for each side and add them all together to get your perimeter

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6x – 2х + 8у – 6y simplified expression

Sholpan [36]

Answer:

4x+2y

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I don’t really understand this type of stuff so please help.

ohaa [14]

For 1 and 2, you plot both lines, and wherever they intersect is the solution to the system. Given the equation of a line, I think the easiest way to plot it is to find two points on the line, then draw a line through them. For example, if $y=5x-1$ , then when $x=0$ , you get $y=-1$ ; when $x=1$ , you get $y=4$ . So plot the points (0, -1) and (1, 4), then strike a line through.

1. Notice that dividing both sides of $2y=10x-2$ by 2 returns $y=5x-1$ , same as the first equation. So the system of equations reduces to one equation, which can have an infinite number of solutions. (This is because for any choice of $x$ or $y$ , you can always find a corresponding value for the other variable.)

2. See attached image. $3x-y=2$ is given by the purple line.

For 3-6, you have several options. The two simplest methods of solving them are by substitution or elimination.

3. Like with (1), notice that dividing both sides of the first equation by 2 gives $x+3y=9$ , so there will be an infinite number of solutions.

4. (by substitution) Since $y=-7x+3$ , we can replace $y$ in the second equation:

$-7x+3+7x=10\implies3=10$

but this is false, so there are no solutions to this system.

5. (by substitution) Since $x=2y+2$ , in the first equation we have

$-5(2y+2)+3y=-10y-10+3y=-7y-10=11\implies-7y=21\implies y=-3$

Then back in the second equation we find

$x=2(-3)+2=-6+2=-4$

So (-4, -3) is the only solution here.

6. (by substitution) Notice that the left hand sides of both equations are the same, so we end up with 7 = 12, but this is false, so no solution exists.