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4 years ago

Use set builder notation to represent the following set. {... -3, -2, -1, 0} {x | x Z, x ≤ 0} {x | x N, x ≤ 0} {x | x R, x ≤ 0}

Mathematics

1 answer:

IceJOKER [234]4 years ago

7 0

Answer:

$\boxed{\boxed{\left\{x\ |\ x\ \epsilon\ Z,\ x \le 0}\right\}}}$

Step-by-step explanation:

Set builder notation-

It is a notation for representing a set by enumerating its elements and stating the properties that its members must satisfy.

The given set is,

$\left \{.... -3, -2, -1, 0 \right \}$

This set is comprised of all negative integers. So symbol Z should be used in this case.

The set builder notation for this set is,

$\left\{x\ |\ x\ \epsilon\ Z,\ x \le 0}\right\}$

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On December 31, 2019, Akron, Inc., purchased 5 percent of Zip Company's common shares on the open market in exchange for $16,050

Anastaziya [24]

The amount reported for the investment in Zip Company by Akron's December 31, 2021, balance sheet is <u>$143,400</u>, which is the fair value of the Common Stock of Zip Company.

<h3>What is the fair value of an investment?</h3>

The fair value of an investment is the current value and not the historical cost when the investment was made.

Fair value refers to the intrinsic worth of an asset or security.

<h3>Data and Calculations:</h3>

Income Dividends Common Stock Akron's Investment

Declared Fair Value (12/31) in Zip Company

2019 $321,000 $16,050 ($321,000 x 5%)

2020 $79,000 $6,200 376,000 $94,000 ($376,000 x 25%)

2021 89,000 15,800 478,000 $143,400 ($478,000 x 30%)

Excess attributed to share of Zip's franchises = $33,350 ($143,400 - $110,050).

Thus, the amount reported for the investment in Zip Company by Akron's December 31, 2021, balance sheet is <u>$143,400.</u>

Learn more about the fair value of an investment at brainly.com/question/13219936

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5 0

1 year ago

What is the decimal multiplier to increase by 5.3?

lisov135 [29]

Answer:

Step-by-step explanation:

to increase 5.3 you multiply it with 10

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3 years ago

Select the correct answer.

alexgriva [62]

Answer:

D. 157

Step-by-step explanation:

4(x^2+3)-2y

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3 0

3 years ago

Read 2 more answers

NEED Help!<br> 111=14g<br> and also 13.65=h + 4.88

crimeas [40]

Answer:

In this question if g and h is constant then;

111 = 14g

14g = 111

g = 111/14

g = 27.7 ~ 28

And also,

13.65 = h + 4.88

h + 4.88 = 13.65

h = 13.65 - 4.88

h = 8.77

Hope it helps!

3 0

3 years ago

A cereal company is exploring new cylinder-shaped containers. Two possible containers are shown in the diagram.x is 6 and r=4.5

KatRina [158]

Answer:

Container $\rm X$ will have less label area than container $\rm Y$ by about $9\; \rm in$ .

Step-by-step explanation:

A rectangular sheet of paper can be rolled into a cylinder. Conversely, the lateral surface of a cylinder can be unrolled into a rectangle- without changing the area of that surface.

Indeed, the width of that rectangle will be the same as the height of the cylinder. On the other hand, the length of that rectangle should be exactly equal to the circumference of the circles on the top and the bottom of the cylinder. In other words, if a cylinder has a height of $h$ and a radius of $r$ at the top and the bottom, then its lateral surface can be unrolled into a rectangle of width $h$ and length $2\,\pi\, r$ .

Apply this reasoning to both cylinder $\mathrm{X}$ and $\rm Y$ :

For cylinder $\mathrm{X}$ , $h = 6\; \rm in$ while $r = 4.5\; \rm in$ . Therefore, when the lateral side of this cylinder is unrolled:

The width of the rectangle will be $6\; \rm in$ , while
The length of the rectangle will be $2 \, \pi \times 4.5\; \rm in = 9\, \pi\; \rm in$ .

That corresponds to a lateral surface area of $54\, \pi\; \rm in^2$ .

For cylinder $\rm Y$ , $h = 10.5\; \rm in$ while $r = 3\; \rm in$ . Similarly, when the lateral side of this cylinder is unrolled:

The width of the rectangle will be $10.5\; \rm in$ , while
The length of the rectangle will be $2\pi\times 3\; \rm in = 6\,\pi \; \rm in$ .

That corresponds to a lateral surface area of $63\,\pi \; \rm in^2$ .

Therefore, the lateral surface area of cylinder $\rm X$ is smaller than that of cylinder $\rm Y$ by $9\,\pi\; \rm in^2$ .

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3 years ago