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8_murik_8 [283]
4 years ago
11

Use set builder notation to represent the following set. {... -3, -2, -1, 0} {x | x Z, x ≤ 0} {x | x N, x ≤ 0} {x | x R, x ≤ 0}

Mathematics
1 answer:
IceJOKER [234]4 years ago
7 0

Answer:

\boxed{\boxed{\left\{x\ |\ x\ \epsilon\ Z,\ x \le 0}\right\}}}

Step-by-step explanation:

Set builder notation-

It is a notation for representing a set by enumerating its elements and stating the properties that its members must satisfy.

The given set is,

\left \{.... -3, -2, -1, 0 \right \}

This set is comprised of all negative integers. So symbol Z should be used in this case.

The set builder notation for this set is,

\left\{x\ |\ x\ \epsilon\ Z,\ x \le 0}\right\}

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Read 2 more answers
Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt
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Using the t-distribution, it is found that since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is <u>tested if it does not outlast by more than 2 hours</u>, that is, the subtraction is not more than 2:

H_0: \mu_B - mu_A \leq 2

At the alternative hypothesis, it is <u>tested if it outlasts by more than 2 hours</u>, that is:

H_1: \mu_B - \mu_A > 2

  • The sample means are: \mu_A = 8.65, \mu_B = 11.23
  • The standard deviations for the samples are s_A = s_B = 0.67

Hence, the standard errors are:

s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934

The distribution of the difference has <u>mean and standard deviation</u> given by:

\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58

s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735

The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 2 is the value tested at the hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{2.58 - 2}{0.2735}

t = 2.12

The critical value for a <u>right-tailed test</u>, as we are testing if the subtraction is greater than a value, with a <u>0.05 significance level</u> and 12 + 12 - 2 = <u>22 df</u> is given by t^{\ast} = 1.71

Since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

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3 years ago
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