The value that makes this true is a
Answer:
The difference between the maximum and minimum is

Step-by-step explanation:
Since p = 10-q, we can replace p in the expression and we get a single-variable function

Taking the derivative with respect to q and using the rule for the derivative of a product

Critical point (where f'(q)=0)
Assuming q≠ 0 and q≠ 10

To check this is maximum, we take the second derivative

and
f''(625/63) < 0
so q=625/63 is a maximum. For this value of q we get p=5/63
The maximum value of

is

The minimum is 0, which is obtained when q=0 and p=10 or q=10 and p=0
The difference between the maximum and minimum is then

-15 7/40
Convert a mixed number by placing the numbers to the right of the decimal over
1000.
Answer:
this question is very hard
Step-by-step explanation: