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Andreyy89
3 years ago
11

Round to the nearest tens place 157

Mathematics
2 answers:
lara [203]3 years ago
6 0
Round to nearest tens place is 167
oksano4ka [1.4K]3 years ago
5 0
160 is the answer for nearest 100= 200 is the ans.
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Answer:

c) A rectangle with width of 9 mm and length of 45 cm.

d) A rectangle with width of 10 cm and length of 44 cm.

Step-by-step explanation:

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Width of the rectangle = 8 in.

First we will find the ratio of length by width.

\frac{length}{width}= \frac{32}{8} = \frac{4}{1} \ \ \ \ equation \ 1

Now we need to find from the given Option which rectangles are not similar to Carl's Rectangle.

So we will check for each.

a) A rectangle with width of 23 cm and length of 92 cm.

we will find the ratio of length by width.

\frac{length}{width}= \frac{92}{23} = \frac{4}{1} \ \ \ \ equation \ 2

By Definition of Similar rectangles which states that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 = equation 2

Hence This rectangle is similar to Carl's rectangle.

b) A rectangle with width of 2.5 inch and length of 10 inch.

we will find the ratio of length by width.

\frac{length}{width}= \frac{10}{2.5} = \frac{4}{1} \ \ \ \ equation \ 2

By Definition of Similar rectangles which states that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 = equation 2

Hence This rectangle is similar to Carl's rectangle.

c) A rectangle with width of 9 mm and length of 45 cm.

we will find the ratio of length by width.

\frac{length}{width}= \frac{45}{9} = \frac{5}{1} \ \ \ \ equation \ 2

By Definition of Similar rectangles which states that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 \neq equation 2

Hence This rectangle is not similar to Carl's rectangle.

d) A rectangle with width of 10 cm and length of 44 cm.

we will find the ratio of length by width.

\frac{length}{width}= \frac{44}{10} = \frac{11}{5} \ \ \ \ equation \ 2

By Definition of Similar rectangles which states that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 \neq equation 2

Hence This rectangle is not similar to Carl's rectangle.

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Step-by-step explanation:

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