Question

How do you solve 2x2-10x-28=0

Answer 1

$2x^2-10x-28=0\ \ \ |:2\\\\x^2-5x-14=0\\\\x^2+2x-7x-14=0\\\\x(x+2)-7(x+2)=0\\\\(x+2)(x-7)=0\iff x+2=0\ \vee\ x-7=0\\\\\boxed{x=-2\ \vee\ x=7}$