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Luba_88 [7]
4 years ago
11

How do you solve 2x2-10x-28=0

Mathematics
1 answer:
musickatia [10]4 years ago
7 0
2x^2-10x-28=0\ \ \ |:2\\\\x^2-5x-14=0\\\\x^2+2x-7x-14=0\\\\x(x+2)-7(x+2)=0\\\\(x+2)(x-7)=0\iff x+2=0\ \vee\ x-7=0\\\\\boxed{x=-2\ \vee\ x=7}
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3 years ago
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Alex777 [14]

Answer:

C

Step-by-step explanation:

|2x - 2| < 8

it implies that

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4 0
3 years ago
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marshall27 [118]

Hello from MrBillDoesMath!

Answer:

y = x/15


Discussion:

Given:

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(2x/5y) 5y = 6 * (5y) =>

2x = 30y =>            (divide both sides by 30)

(2/30)x = y =>

y = x/15


( or you could also multiply both sides of the original equation by "y" and then divide both sides by 6)

Thank you,

MrB

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4 years ago
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After translating this figure 7 units left and 1 unit down, what is the final orientation of the transformed figure and which qu
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Step-by-step explanation:

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