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equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)
Perpendicular bisector lies at the midpoint of a line
Lets find mid point of (-9,-8) and (7,-4)
midpoint formula is
midpoint is (-1, -6)
Now find the slope of the given line
(-9,-8) and (7,-4)
Slope of perpendicular line is negative reciprocal of slope of given line
So slope of perpendicular line is -4
slope = -4 and midpoint is (-1,-6)
y - y1 = m(x-x1)
y - (-6) = -4(x-(-1))
y + 6 = -4(x+1)
y + 6 = -4x -4
Subtract 6 on both sides
y = -4x -4-6
y= -4x -10
equation for the perpendicular Bisector y = -4x - 10
You have to consider the “ends” of the x-axis, the far right (for infinitely large values of x) and left (for infinitely small values of x) of the graph.
From the diagram above you can see that:
- When
then
(notice that as the values of x get smaller and smaller, the graph gets closer and closer to the line y=1);
- When
then
(notice that as the values of x get larger and larger, the graph gets closer and closer to the line y=1).
Answer: correct choice is D.