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sergeinik [125]
3 years ago
11

Write an equation of the parabola in vertex form.

Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0
Vertex Form of Quadratic Equation - MathBitsNotebook(A1 - CCSS Math) f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. FYI: Different textbooks have different interpretations of the reference "standard form" of a quadratic function...:)
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butalik [34]
Ya that's correct u got the right answer
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3 years ago
A textbook company keeps track of its daily cost for printing whole textbooks to different schools, but can only print up to 500
seraphim [82]
Part A: Chose some value for x, that means any amount of books to print for example 100 books, so x=100
Replace x=100 in C(x) and solve:
C(100)=3.5*100+1200=1550
Part B: Replace C(x) by 1900 and solve for x from the given equation:
1900=3.5x+1200
3.5x=1900-1200
x=700/3.5= 200
Part C: the statement C(20)=1270 means that 1270 is the cost for printing 20 books.
Part E: C(40.5)=1341.75 I think this statement is incorrect given the context because x means number of books to print so this value must be an integer number.
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3 years ago
Tessa is training for a marathon she runs 13 km a day for 3 days
creativ13 [48]

nice

i think there's supposed to be more to the problem lol

4 0
2 years ago
Read 3 more answers
In ΔJKL, l = 860 inches, j = 920 inches and ∠K=126°. Find ∠L, to the nearest degree.
fomenos

Answer:

26

Step-by-step explanation:

JKL= ABC,  jkl=abc

1.) use law of sines to find k.

c^{2} =a^{2} +b^{2} -2abCosC    

c=\sqrt{920^{2} +860^{2} -2(920)(860)cos(126) } = 1586.225515

2.) use law of cosines to find L

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}  

plug in for b and c:  \frac{860}{sinB} =\frac{1586.225515}{sin126}

cross multiply: \frac{1586.23sinB}{1586.23} =\frac{860sin126}{1586.23}

sinB= 0.4386227612\\B=sin^-1(0.4386227612)= 26.01604086\\

L=26

5 0
3 years ago
After a 10% discount it became $450?
REY [17]
0.9x = 450
x = 450/0.9
x = 500

Answer = 500
7 0
3 years ago
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