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2 years ago

I need help please!!!

Mathematics

1 answer:

vazorg [7]2 years ago

6 0

963i think its probaly wrong

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Misha found that the equation -|2x-10|-1=2 had two possible solution x=3.5and x =-6.5. Which explains whether or not her solutio

Vika [28.1K]

<span>-|2x-10|-1=2 has NO solutions, because the absolute value function is never negative. Can be 0, can be positive, but can NOT be negative.

</span>

3 0

3 years ago

Read 2 more answers

hich uses the high-low method to analyze cost behavior, has determined that machine hours best predict the company's total ut

Crank

Answer:

1)- Variable utilities cost per machine hour = 1.6 per machine hour

2)- Fixed cost = 1740

3)-Total cost on 1220 Machine hour will be

= 3692

Step-by-step explanation:

1) CALCULATE VARIABLE UTILITIES COST PER MACHINE HOUR :

Variable utilities cost per machine hour = Change in cost/high machine hour-low machine hour

=4076-3388/1460-1030

Variable utilities cost per machine hour = 1.6 per machine hour

2) Fixed cost = Total cost-variable cost

= 3388-(1030*1.6)

Fixed cost = 1740

3) Total cost on 1220 Machine hour will be (1220*1.6+1740) = 3692

3 0

2 years ago

Find the value of x in the parallelogram below.

alina1380 [7]

Answer:

102

Step-by-step explanation:

78 and x are adjacent angles.

Sum of adjacent angles is 180 in a parallelogram.

78 + x = 180

x = 180 - 78

x = 102

8 0

2 years ago

Read 2 more answers

The number of errors in a textbook follow a poisson distribution with a mean of 0.01 errors per page. what is the probability th

neonofarm [45]

Mean number of errors in each page = 0.01
Mean number of errors in 100 pages = 0.01*100=1

It is possible to use the cumulative distribution function (CMF), but the math is a little more complex, involving the gamma-function. Tables and software are available for that purpose.

Thus it is easier to evaluate with a calculator for the individual cases of k=0,1,2 and 3.

The Poisson distribution has a PMF (probability mass function)

$P(k):=\frac{\lambda^ke^{-\lambda}}{k!}$
with λ = 1
=>
$P(0):=\frac{1^0e^{-1}}{0!}=0.3678794$
$P(1):=\frac{1^1e^{-1}}{1!}=0.3678794$
$P(2):=\frac{1^2e^{-1}}{2!}=0.1839397$
$P(3):=\frac{1^3e^{-1}}{3!}=0.0613132$
=>
$P(k$
or
P(k<=3)=0.9810 (to four decimal places)

3 0

2 years ago

Fynjy0 [20]

Answer:

PQ R s parallelogram

< Q = < s = 114

< P = 180 _ 114 = 66

<2 = 66 / 2 = 33

< I = 114 / 2 = 5 7

< I + < 2 = 3 3 + 57 = 90

< ( STP ) = 90

TP I ST

3 0

3 years ago