$x^2-y^2=2\\ \underline{x^2+y^2=4}\\\\ 2x^2=6\\ x^2=3\\ x=-\sqrt3 \vee x=\sqrt3\\\\ 3+y^2=4\\ y^2=1\\ y=-1 \vee y=1\\\\ x\in\{(-\sqrt3,-1),(-\sqrt3,1),(\sqrt3,-1),(\sqrt3,1)\}$

So, there are 4 solutions.

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How to use techniques of adding the additive inverse and multiplying by the Students use algebra to solve equations (of the form px + q = r and p(x + q) = r where p pay with a $10 bill and receive no change, then how much did each bottle of a. If Allen buys 4 uniform shirts at one time, he gets a $10 discount so that the

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