X+109 and x+89 what is x they need to be the same number when finished

Who can do this question, I don't know how to do...this is difficult for me....who can teach me?

cupoosta [38]

We know that AB and CD are parallel. This allows many assumptions.
From that we know that angle A and angle D are congruent.
That means that x + 8 = 2x - 22 and we can solve for x
x + 8 = 2x - 22
x + 30 = 2x
30 = x or x = 30

We know from the figure that angle B is x or now that we solved for x is 30 degrees. Also, we know that both angle A and angle D are 38 degrees. Now we can solve for the vertical angle E which has a measure of y degrees. A triangle has the sum of its angles equal to 180 degrees.

We can set up an equation like this 30 + 38 + y = 180
30 + 38 + y = 180
68 + y = 180
y = 112 degrees

That is how you would solve this problem

4 0

3 years ago

I'm struggling fr now, pls can you help me answer these questions using the y= mx+ c method thanks!

Phoenix [80]

Answer:

Examination of the equation shows (graph):

x = 0, y = .5

Then .5 = c gives us the value of c giving

y = m x + .5 is our equation

Using y = 0, x = -1 gives

o = -1 * m + .5

m = .5

y = .5 x + .5 for the final equation

Check:

At x = 5, y = 3

3 = .5 (5) + .5 = 3

4 0

2 years ago

Luda [366]

Answer:

a) H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

b) $\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

c) $\chi^2_{crit}=5.991$

d) Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

High school Some College Bachelor or higher Total

Public Broadcasting 15 15 10 40

Commercial stations 5 25 10 40

Total 20 40 20 80

We need to conduct a chi square test in order to check the following hypothesis:

Part a

H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

The level os significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

Part b

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{20*40}{80}=10$

$E_{2} =\frac{40*40}{80}=20$

$E_{3} =\frac{20*40}{80}=10$

$E_{4} =\frac{20*40}{80}=10$

$E_{5} =\frac{40*40}{80}=20$

$E_{6} =\frac{20*40}{80}=10$

And the expected values are given by:

High school Some College Bachelor or higher Total

Public Broadcasting 10 20 10 40

Commercial stations 10 10 20 40

Total 20 30 30 80

Part b

And now we can calculate the statistic:

$\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(2-1)(3-1)=2$

Part c

In order to find the critical value we need to look on the right tail of the chi square distribution with 2 degrees of freedom a value that accumulates 0.05 of the area. And this value is $\chi^2_{crit}=5.991$

Part d

And we can calculate the p value given by:

$p_v = P(\chi^2_{3} >33.75)=2.23x10^{-7}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(33.75,2,TRUE)"

Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

7 0

3 years ago

A coat cost $ 131.61 with 9.5% sales tax

marysya [2.9K]

Calculating Total Cost. Multiply the cost of an item or service by the sales tax in order to find out the total cost. The equation looks like this: Item or service cost x sales tax (in decimal form) = total sales tax. Add the total sales tax to the Item or service cost to get your total cost. Multiply retail price by tax rate

Let's say you're buying a $100 item with a sales tax of 5%. Your math would be simply: [cost of the item] x [percentage as a decimal] = [sales tax]. That's $100 x .

6 0

3 years ago

Solve the system y = -x + 7 and y = -0.5(x - 3)2 + 8<br> I'll mark the brainliest!!!!!!!!!

hram777 [196]

Answer:

(1, 6)

(7, 0)

Step-by-step explanation:

y = -x + 7

y = -0.5(x - 3)² + 8

-x + 7 = -0.5(x - 3)² + 8

-x + 7 = -0.5(x² - 6x + 9) + 8

-x + 7 = -0.5x² + 3x - 4.5 + 8

0 = -0.5x² + 4x - 3.5

0 = x² - 8x + 7

0 = (x - 7)(x - 1)

x - 7 = 0 or x - 1 = 0

x = 1 or 7

7 0

3 years ago

Read 2 more answers