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Natali5045456 [20]
3 years ago
13

Assume you have a int variable n that has already been declared and initialized. Its value is the number of integers that need t

o be read in from standard input and printed out in sorted (ascending) order, each on a line by itself. Furthermore, there are no duplicates in the input and every number to be read is a non-negative value that is less than n's value. In this exercise you may not use any array (or fancy STL collection such as a vector). You may declare a variable or two as needed. With these restrictions, read the n values and print them out as required onto standard output.
Computers and Technology
1 answer:
Aleks [24]3 years ago
5 0

Answer:

/*This program is in c++*/

# include<iostream>

#include<stdio.h>

using namespace:; std;

int main()

{

 int n, a[20]; /* n can be maximum 20*/

 cout<<"Enter the value of n";

 cin>>n;

 For (int i=0;i<=n;i++)

{

  cout<<"The number must be less than"<<n;

  cin>>a[i];

}

int k=a[0];

for(int j=0;j<=n;j++)

{

   if(a[i]<k)

     {  

          a[i];=k

         k=a[i];

     }

     else

     {

          continue;

      }

}

cout<<"The numbers in ascending order are:";

for{int m=0;i<=n;i++)

{

    cout<<"a[i];

}

return 0;

}

         

Explanation:

The program is self explanatory.

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Therefore, Option (D) is correct.

 

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it is . org Explanation:

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As you are talking to your colleague over the phone, the sound of an airplane flying low drowns out part of your conversation. I
Rasek [7]

Answer:

Interference.

Explanation:

As the user is communicating with their friend through the mobile, most of their interaction is interrupted by the noise of an airplane flying at low hight. Instantly afterward, the user's mobile phone rang, disrupting the communication once more.  

So, according to the following scenario both of those are examples of interference.

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Write a C++ programthat reads in the side of a square and prints out a pattern on$
AnnZ [28]

Answer:

#include<iostream>

using namespace std;

//main function

int main(){

   //initialize the variables

   int side;

   //print the message

   cout<<"Please enter the side of square: ";

   cin>>side;  //read the vale and store in the variable.

   // for loop

   for(int i=1;i<=side;i++){  //lop for rows

       for(int j=1;j<=side;j++){   //loop for column

           cout<<"$";  //print the '*'

       }

       cout<<endl;

   }

}

Explanation:

Create the main function and declare the variable side.

print the message on the screen for the user and then store value enter by the user on the variable side.

take the nested for loop for print the pattern.

nested for loop means, loop inside another loop it is used for print the pattern having rows and columns.

the first loop updates the row number and the second the loop print the character '$' in the column-wise.

in the code,

if i = 1, for loop check the condition 1 <= 5 if the value of side is assume 5.

condition is true and the program moves to the second for loop and starts to print the character '$' five times after that, print the new line.

then, the above process repeat for different rows and finally, we get the pattern in square shape.

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