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Natali5045456 [20]
3 years ago
13

Assume you have a int variable n that has already been declared and initialized. Its value is the number of integers that need t

o be read in from standard input and printed out in sorted (ascending) order, each on a line by itself. Furthermore, there are no duplicates in the input and every number to be read is a non-negative value that is less than n's value. In this exercise you may not use any array (or fancy STL collection such as a vector). You may declare a variable or two as needed. With these restrictions, read the n values and print them out as required onto standard output.
Computers and Technology
1 answer:
Aleks [24]3 years ago
5 0

Answer:

/*This program is in c++*/

# include<iostream>

#include<stdio.h>

using namespace:; std;

int main()

{

 int n, a[20]; /* n can be maximum 20*/

 cout<<"Enter the value of n";

 cin>>n;

 For (int i=0;i<=n;i++)

{

  cout<<"The number must be less than"<<n;

  cin>>a[i];

}

int k=a[0];

for(int j=0;j<=n;j++)

{

   if(a[i]<k)

     {  

          a[i];=k

         k=a[i];

     }

     else

     {

          continue;

      }

}

cout<<"The numbers in ascending order are:";

for{int m=0;i<=n;i++)

{

    cout<<"a[i];

}

return 0;

}

         

Explanation:

The program is self explanatory.

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