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expeople1 [14]
3 years ago
14

HELP PLSSSSS!!! I WILL MARK BRAINLIEST FOR THE FIRST AND CORRECT ANSWER!!!

Computers and Technology
2 answers:
dalvyx [7]3 years ago
6 0
The answer you are looking for would be A. Hardware can be an external tool, where as software is an internal tool. Hope this helped!
Murrr4er [49]3 years ago
3 0

Answer:

The correct answer is A

Explanation:

You might be interested in
How can an exception be explicitly raised in C++? How are exceptions bound to handlers in C++?
xenn [34]

Answer:

Exceptions are raised using throw statement in c++.

Explanation:

Try block is used to keep the statements which we felt that they will raise an exception. Catch block is used to catch the exception which is thrown by the try block.

#include<iostream.h>

void main(){

int x,y,z;

try{

cout<"enter 2 numbers";

cin>>x>>y;

if(y==0)

throw y;

z=x/y;

}

catch(int x){

cout<<"exception caught";

}

}

4 0
3 years ago
Join my among us <br><br> code GNLMJF
ryzh [129]

Answer:

i cant

Explanation:

i would but im on a chromebook rn

sorry but thanks

take care

8 0
3 years ago
Read 2 more answers
5. What skill is unique to reading online?
torisob [31]
Ignoring distractions like hyperlinks and advertisements
6 0
3 years ago
Please help lots of points worth
Artemon [7]

Answer:

i dont rlly know the first one i mean i guess you cud say the last one? i dunno  srry but the 2nd one is definitively    is Laura woke up to the alarm clock screaming

Explanation:

6 0
3 years ago
2. Create a file with the follow integer/string content and save it as fun.txt. 6 fun. 3 hello 10 &lt;&gt; 2 25 4 wow! Write an
Nesterboy [21]

Answer:

see explaination

Explanation:

I made use of python program to solve this.

text file name with fun.txt.

6 fun. 3 hello 10 <> 2 25 4 wow!

Program code:

import re

file = open('fun.txt','r') #for reading file

strings="" #declaring empty string

for k in file:

strings=strings+k #all character in file is storing in strings variable for do operations

pattern = '\s' #for pattern \s is for space

result = re.split(pattern, strings) #split the string with space

for k in range(len(result)): #loop through the list of string

if(k%2) == 0: #checking for integer to time of string

p=int(result[k])

print(result[k+1] *p) #print times of the string(k+1)

Check attachment for output

8 0
3 years ago
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