Check the picture below.
how do we know? well, notice h(t), starts off at 12, up up up reaches 47.84 then down down down, which is pretty much the trajectory of a flying object, by the time it gets to 44, is still going down.
now, let's look at g(t), starts off at 10, and goes up up up, never down, by the time it gets to 41, is still going up,
so at second 2, h(t) is 44 and going down, g(t) is 41 and going up, at 2.2 h(t) is 40.16, and g(t) is 44.1, between that lapse, h(t) became 44, 43, 42, 41, in the same lapse g(t) became 41, 42, 43, 44, so somewhere in those values h(t) = g(t).
what does the solution mean? It's the seconds or the instant lapse when the first cannon ball was at the same height as the second cannonball.
Answer:
the scale factor is 2, but x is 11
Step-by-step explanation:
IQR for the data {1, 3, 4, 8, 20} is 5.
Interquartile Range(IQR) for a data is defined as the difference between third quartile and first quartile.
denoted by IQR=Q₃-Q₁ (Q₃ is third quartile and Q₁ is first quartile)
The five number summary of a data set is represented as
{minimum, first quartile , second quartile , third quartile , maximum}..…(1)
According to the question
{1, 3, 4, 8, 20}
On comparing it with equation …(1)
minimum=1
Q₁ =3 , Q₂=4 , Q₃=8 , maximum =20
IQR=Q₃-Q₁
Substituting the values we get
IQR=8-3=5.
Therefore , Interquartile Range for the data {1, 3, 4, 8, 20} is 5.
Learn more about Inter Quartile Range here brainly.com/question/28037049
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Answer:
A = 121 pi in^2
Step-by-step explanation:
The circumference is given by
C = 2 * pi*r
22 pi = 2 * pi *r
Divide each side by 2 pi
22 pi / (2 pi) = 2 pi r / (2pi)
11 = r
Now find the area
A = pi r^2
A = pi (11)^2
A = 121 pi in^2
Answer:
.0075 (hope this help; let me know if not)
Step-by-step explanation:
The operation is + and the signs of the numbers are opposite so we have to subtract. The bigger number has positive sign in front if so we do 1.2-1.125=1.200-1.125
I'm going to line up
1.200
-1.125
---------
If you have 200 and you take about 125... 75 should beleft
so
1.200
-1.125
---------
0.075
