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masya89 [10]
3 years ago
7

Round 38.86 to one decimal place

Mathematics
2 answers:
Xelga [282]3 years ago
8 0
Round to one decimal place
so you round the .8 
look at the hundredth place and you see 6 so round up
38.9
densk [106]3 years ago
7 0
When rounding to one decimal place, that means to round only the first number after the dot which is 8, but then you have to look at the second number to see if you need to change the first number or not and since the second number is above 4 then you gotta round it up to 9. so the answer would be 38.9
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HELP PLEASE PLEASE PLEASE!!The function f(x) = 4x – 8 is reflected across the y-axis, resulting in a new function, g(x). Write t
MaRussiya [10]
Not sure but I think g(x)= -4x -8
The minus makes the graph descend and therefore it's on the other site of the y-axis (sorry for my English haha...I'm not a native speaker)
3 0
3 years ago
All of these ODEs model a system with a spring, mass and dashpot.
Wewaii [24]

Answer:

− 3 y ' ' − 3 y ' + 3 y = 0 : over-damped

− 2 y ' ' − 4 y ' + 1 y = 0 : over-damped

1 y ' ' + 7 y ' + 5 y = 0: over-damped

Step-by-step explanation:

Using the characteristic equation you can express a differential equation of order n as an algebraic equation of degree n:

a_ny^n+a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

This differential equation will have a characteristic equation of the form:

a_nr^n+a_n_-_1r^{n-1}+...+a_1r+a_o=0

Now, you can classify the solution for a differential equation using a simple method. In order to do it, you just need to use the discriminant.

  • If the discriminant is greater than zero, the solution is over-damped

  • If the discriminant is less than zero, the solution is under-damped

  • If the discriminant is equal to zero, the solution is critically damped

So, given the differential equation:

-3y''-3y+3y=0

Which has characteristic equation of the form:

-3r^2-3r+3=0

The quadratic polynomial of the form:

ar^2+br+c=0

Has discriminant:

Disc=b^2-4ac

In this case:

a=-3\\b=-3\\c=3

So:

Disc=(-3)^2-4(-3)(3)=9-(-36)=45

In this case:

Disc=45>0

Therefore the solution is over-damped.

Now, given the differential equation:

-2y''-4y'+1y=0

Which has characteristic equation of the form:

-2r^2-4r+1=0

The quadratic polynomial of the form:

ar^2+br+c=0

Has discriminant:

Disc=b^2-4ac

In this case:

a=-2\\b=-4\\c=1

So:

Disc=(-4)^2-4(-2)(1)=16+8=24

In this case:

Disc=24>0

Therefore the solution is over-damped.

Finally, given the differential equation:

1y''+7y'+5y=0

Which has characteristic equation of the form:

1r^2+7r+5=0

The quadratic polynomial of the form:

ar^2+br+c=0

Has discriminant:

Disc=b^2-4ac

In this case:

a=1\\b=7\\c=5

So:

Disc=(7)^2-4(1)(5)=49-20=29

In this case:

Disc=29>0

Therefore the solution is over-damped.

6 0
3 years ago
Simplify (Remember to simplify means to write an equivalent expression that uses each variable on')
DaniilM [7]

Answer:

A) x^{3} y^{4}

B) -\frac{5x^{2} }{y}

C) 9m^{4}n^{4}

D)\frac{1}{x^{3} }

Step-by-step explanation:

Hope this helps.

6 0
2 years ago
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eduard
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6 0
3 years ago
Read 2 more answers
(picture is sideways)
Vlada [557]

Answer:

U=80

B=44

Q=93

Step-by-step explanation:

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180=U+100

180-100=U+100-100

80=U

B:180=B+90+46

180=B+136

180-136=B+136-136

44=B

Q:180=Q+36+51

180=Q+87

180-87=Q+87-87

93=Q

4 0
3 years ago
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