HELP ME PLZZ I NEED HELP WITH THIS !!

PLS ANSWER ASAP

Gnoma [55]

9514 1404 393

Explanation:

The inverse of a function y = f(x) can be found by solving x = f(y) for y.

When we do that here, we find ...

$x=f(y)\\\\x=\dfrac{y+a}{b}\\\\bx=y+a\\\\y=bx-a$

When we compare this to g(x), which we want to be the inverse of f(x), we see that ...

cx -d = bx -a ⇒ b=c, and d=a

We can choose a=d=1 and b=c=2 to make the two functions inverses:

f(x) = (x +1)/2

g(x) = 2x -1

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The inverse of f(x) is g(x) if f(g(x)) = x.

f(g(x)) = ((2x -1) +1)/2 = 2x/1 = x . . . . . g is the inverse of f

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Same as Part 2, but in reverse.

g(f(x)) = 2((x +1)/2) -1 = (x +1) -1 = x

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The attachment is a graph of the two functions and a table of values. The line y=x is the dashed orange line. You will notice that f(x) and g(x) are reflections of each other across that line.

6 0

3 years ago

The measures of the angles of Triangular garden are in the ratio 2:5:5. What are the measures of the angles? Classify the triang

Darina [25.2K]

2x + 3x + 5x = 180

10x = 180

x = 18

2x = 36, 3x = 54, 5x = 90

They add up to 180 (definition of sum of angles of a triangle.)

6 0

3 years ago

Find the area of a right triangle with side lengths 12, 35, and 37. The length of the altitude to the hypotenuse is 11.35

Snowcat [4.5K]

I got 209.975 units squared

3 0

3 years ago

Can you help me with this please???

11111nata11111 [884]

Answer:

C

Step-by-step explanation:

divide 14 by 4 to solve it, you get 3.5 or 3 1/2

6 0

2 years ago

ALGEBRAIC EXPRESSION 11. Subtract the sum of 13x – 4y + 7z and – 6z + 6x + 3y from the sum of 6x – 4y – 4z and 2x + 4y – 7. 12.

Naily [24]

Answer:

Explained below.

Step-by-step explanation:

(11)

Subtract the sum of (13x - 4y + 7z) and (- 6z + 6x + 3y) from the sum of (6x - 4y - 4z) and (2x + 4y - 7z).

$[(6x - 4y - 4z) +(2x + 4y - 7z)]-[(13x - 4y + 7z) + (- 6z + 6x + 3y) ]\\=[6x-4y-4z+2x+4y-7z]-[13x-4y+7z-6z+6x+3y]\\=6x-4y-4z+2x+4y-7z-13x+4y-7z+6z-6x-3y\\=(6x+2x-13x-6x)+(4y-4y+4y-3y)-(4z+7z+7z-6z)\\=-11x+y-12z$

Thus, the final expression is (-11x + y - 12z).

(12)

From the sum of (x² + 3y² - 6xy), (2x² - y² + 8xy), (y² + 8) and (x² - 3xy) subtract (-3x² + 4y² - xy + x - y + 3).

$[(x^{2} + 3y^{2} - 6xy)+(2x^{2} - y^{2} + 8xy)+(y^{2} + 8)+(x^{2} - 3xy)] - [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[x^{2} + 3y^{2} - 6xy+2x^{2} - y^{2} + 8xy+y^{2} + 8+x^{2} - 3xy]- [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[4x^{2}+3y^{2}-xy+8]-[-3x^{2} + 4y^{2} - xy + x - y + 3]\\=4x^{2}+3y^{2}-xy+8+3x^{2}-4y^{2}+xy-x+y-3\\=7x^{2}-y^{2}-x+y+5$

Thus, the final expression is (7x² - y² - x + y + 5).

(13)

What should be subtracted from (x² – xy + y² – x + y + 3) to obtain (-x²+ 3y²- 4xy + 1)?

$A=(x^{2} - xy + y^{2} - x + y + 3) - (-x^{2}+ 3y^{2}- 4xy + 1)\\=x^{2} - xy + y^{2} - x + y + 3 +x^{2}- 3y^{2}+ 4xy -1\\=2x^{2}-2y^{2}+3xy-x+y+2$

Thus, the expression is (2x² - 2y² + 3xy - x + y + 2).

(14)

What should be added to (xy – 3yz + 4zx) to get (4xy – 3zx + 4yz + 7)?

$A=(4xy-3zx + 4yz + 7)-(xy - 3yz + 4zx) \\=4xy-3zx + 4yz + 7 -xy + 3yz - 4zx\\=3xy-7zx+7yz+7$

Thus, the expression is (3xy - 7zx + 7yz + 7).

(15)

How much is (x² − 2xy + 3y²) less than (2x² − 3y² + xy)?

$A=(2x^{2} - 3y^{2} + xy)-(x^{2} - 2xy + 3y^{2})\\=2x^{2} - 3y^{2} + xy-x^{2} + 2xy - 3y^{2}\\=x^{2}-6y^{2}+3xy$

Thus, the expression is (x² - 6y² + 3xy).

7 0

3 years ago