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3 years ago

Nina can braid 48 inches of rope in 1 hour. what is her speed in feet per hour?

Mathematics

1 answer:

mr Goodwill [35]3 years ago

3 0

There are 4 feet in 48 inches, so your answer should just be 4 feet per hour.

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What is the surface area of this square pyramid? <br> HELP!

aniked [119]

Answer:

A≈149.84

Step-by-step explanation:

A=a2+2aa2

4+h2=62+2·6·62

4+92≈149.842

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3 years ago

A plane flew 525 miles in 1.75 hours. Find the average speed of the plane.

ale4655 [162]

We are trying to find the average speed of the plane, which is mph, or $\dfrac{\textrm{miles}}{\textrm{hour}}$ . Using proportions, we can find the average speed of the plane in mph:

$\dfrac{525 \,\, \textrm{miles}}{1.75 \,\,\textrm{hours}} = \dfrac{x \,\, \textrm{miles}}{1 \,\,\textrm{hour}}$

Use the information from the problem to create a proportion. Remember that we are looking for mph, so we will call that $x$ .

$\dfrac{525}{1.75} \,\textrm{miles} = x \,\textrm{miles}$

Multiply the entire equation by $1 \,\textrm{hour}$

$\dfrac{525}{1.75} = 300 = x$

Divide both sides of the equation by $1 \,\textrm{mile}$ to clear both sides of the mile unit

The average speed of the plane is 300 mph.

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3 years ago

Dean used a triple beam balance to find that the mass of a rock was 40 g and he used a graduate cylinder that measures the volum

zhenek [66]

Answer:

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Step-by-step explanation:

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2 years ago

: The proliferation of the Internet has given rise to a new method of advertising, called spamming, that essentially is a more c

Dmitry [639]

The number of potential customers that the company has reached is 10,000 e--mail addresses.

<h3>What is a word problem in mathematics?</h3>

A word problem is a real-life problem and it can be approached with the use of a mathematical model, interpretation into variables, and arithmetic operations usage.

Given that:

A company buys three mailing lists with 2500, 3500, and 4000 addresses respectively.

The number of potential customers that the company has reached is:

= 2500 3500 + 4000 e--mail addresses.

= 10,000 e--mail addresses.

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2 years ago

Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places

natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

$\rm 5 \sin \theta = 4\\\\\theta = 0.927 , 2.214$

Then by the integration, we have

$\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\$

$\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\$

On solving, we have

$\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75$

Thus, the area of the region is 3.75 square units.

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2 years ago