Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Since the midpoint lies on the axis, both ends are therefore equidistant from the axis and are mirrors of each other so..
Q = (4,9)
21 I think cause you use pemdas
Answer:
Hey sisters!
Step-by-step explanation:
Answer:
21
Step-by-step explanation:
(-4)(-2)+2(6+5)
(8)+2(11)
10+11
21
Hope this helps! :)
