Answer:For every right triangle, the circumcenter is always the midpoint of the hypotenuse. All four points of concurrency can themselves be concurrent! Only with an equilateral triangle will the centroid, circumcenter, incenter and orthocenter always be the same point!
Step-by-step explanation:
Answer:
k = 8
Step-by-step explanation:
8(10 - k) = 2k
First, distribute within the parenthesis,
80 - 8k = 2k
Add 8k to both sides of the equation
80 = 10k
Divide both sides by 10 to get your answer
8 = k
I hope this helps :)
<h3>I'll teach you how to solve (m^2-m-4)+(m+5)</h3>
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(m^2-m-4)+(m+5)
Remove parentheses:
m^2-m-4 + m+5
Group like terms:
m^2-m+m-4+5
Add similar elements:
m^2-4+5
Add/subtract the numbers:
m^2+1
Your Answer Is m^2+1
plz mark me as brainliest if this helped :)
the equation becomes y> 2x+5,
the graph would be C
Answer:
it is c because i took test review
Step-by-step explanation:
