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3 years ago

Which point of concurrency is always on the vertex of a right triangle

1 answer:

8 0

Answer:For every right triangle, the circumcenter is always the midpoint of the hypotenuse. All four points of concurrency can themselves be concurrent! Only with an equilateral triangle will the centroid, circumcenter, incenter and orthocenter always be the same point!

Step-by-step explanation:

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Find the solutions below x^2-4 check all that apply

Assoli18 [71]

Answer:(x+2)(x−2)

Step-by-step explanation:Since both terms are perfect squares, factor using the difference of squares formula

3 0

4 years ago

Which equation results from adding the equations in this system? x + 6 y = 9. Negative x + 2 y = negative 15. 8 y = negative 6 8

nignag [31]

Answer:

8y = - 6

Step-by-step explanation:

Given the 2 equations

x + 6y = 9 → (1)

- x + 2y = - 15 → (2)

Adding the 2 equations term by term gives

(x - x) + (6y + 2y) = (9 - 15), that is

8y = - 6

8 0

4 years ago

Read 2 more answers

A certain town never has two sunny days in a row. Each day is classified as being either sunny, cloudy (but dry), or rainy. If i

Vikentia [17]

Answer:

In the long run if one day is rainy there is frequency of 2/5 that other two days will also be rainy.

Step-by-step explanation:

A matrix is formed to classify the weather conditions. It is given that if one day is sunny then there is likely chance that the next day will be cloudy, but if one day is rainy then there is 60% chance that next day will be same. To identify the possibility of next two days we create probability matrix;

Probability (P) = $\left[\begin{array}{ccc}0&\frac{1}{2} &\frac{1}{2} \\\frac{1}{4} &\frac{1}{2} &\frac{1}{4} \\\frac{1}{4} &\frac{1}{4} &\frac{1}{2} \end{array}\right]$

After solving for probability we get a fraction of 2/5

8 0

3 years ago

How does division affect numbers? Give an example and explain the your example and answer

Alja [10]

Division affects numbers by splitting them up into neat little groups.

For example, we can say we have 68 marbles and want to split them into 4 piles. For this, we can make the division problem 68 / 4 = ?

In this example, we are saying that we are splitting 68 marbles into 4 even groups. If we are doing it evenly, how many marbles are in each pile?

68 / 4 = 17

There are 17 marbles in each of the 4 piles. We can check our work by adding:

17 + 17 + 17 + 17 = 68

And the math checks out.
Hope this helped =)

4 0

4 years ago

The sales of a grocery store had an average of $7,000 per day. The store introduced several advertising campaigns in order to in

Sati [7]

Answer:

a.The advertising campaigns increased the average daily sales.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the advertising campaigns increased the average daily sales.

Then, the null and alternative hypothesis are:

$H_0: \mu=7000\\\\H_a:\mu> 7000$

The significance level is 0.05.

The sample has a size n=100.

The sample mean is M=7280.

The standard deviation of the population is known and has a value of σ=1000.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1000}{\sqrt{100}}=100$

Then, we can calculate the z-statistic as:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{7280-7000}{100}=\dfrac{280}{100}=2.8$

This test is a right-tailed test, so the P-value for this test is calculated as:

$\text{P-value}=P(z>2.8)=0.0026$

As the P-value (0.0026) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the advertising campaigns increased the average daily sales.

7 0

3 years ago