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jeka94
3 years ago
5

11. Write the equation in slope intercept form that has a slope of -23 and passes through the point (-1, 2).

Mathematics
1 answer:
insens350 [35]3 years ago
7 0
11. y = -23x - 21

You can get this by starting with y = mx + b (slope intercept form). Then put in all the knowns and solve for the b. 

2 = -23(-1) + b
2 = 23 + b
-21 = b

Then add that to the end of the equation with m = -23

12. -5

The y-intercept of an equation is always the number added on at the end of an equation. It is also the number with no x attached to it. 

13. 8x^9y^6

When you use the law of exponents, you need to make sure the exponent goes to each individual term. When we cube the 2, it becomes 8. When you cube x^3, you get x^3*x^3*x^3 or x^9. And with y^2 you get y^6 
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Find the slope of the line passing through the points (3, 4) and (8, -3).
aalyn [17]

Answer:

<h2>         \bold{m=-1\dfrac25}</h2>

Step-by-step explanation:

The slope of the line passing through two given points:  m=\dfrac{y_2-y_1}{x_2-x_1}

(3, 4)   ⇒   x₁ = 3,  y₁ = 4

(8, -3)   ⇒     x₂ = 8,  y₂ = -3

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3 years ago
Find the values of x (if any) at which f(x)= x+1/x^2-1 is not continuous. If so, is the discontinuity removable?
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f(x)=\dfrac{x+1}{x^2-1} has two points of discontinuity at x=\pm1, where x^2-1=0.

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so as long as x\neq-1, we can cancel x+1 and be left with \dfrac1{x-1}. Then as x\to-1, we have

\displaystyle\lim_{x\to-1}f(x)=\lim_{x\to-1}\frac1{x-1}=-\frac12

The limit exists, so the discontinuity at -1 is removable (so definitely not C or D).

Meanwhile,

\displaystyle\lim_{x\to1}f(x)=\lim_{x\to1}\frac1{x-1}

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You multiply 3 by 16 and that gives you 48

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3 0
3 years ago
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