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Sergeu [11.5K]
4 years ago
10

90% of the students in a high school have a cell phone. if there are 750 students in the school, how many of the students have c

ell phones
Mathematics
1 answer:
kaheart [24]4 years ago
8 0

Answer:

675

Step-by-step explanation:

750 gets turned into 7.50, or 7.5. Then you multiply 7.5 by 90 to get your answer

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In the triangle shown we can find the angle θ as follows calculator
Xelga [282]
Given a right triangle with hypothenus of measure 34, the side opposite the angle θ of measure 30, and the side adjacent the angle theta of measure 16.

\sin\theta= \frac{opposite}{hypothenuse} = \frac{30}{34} = \frac{15}{17}  \\  \\ \Rightarrow \theta=\sin^{-1}\left( \frac{15}{17} \right) \\  \\  \\ \cos\theta= \frac{adjacent}{hypothenuse} = \frac{16}{34} = \frac{8}{17}  \\  \\ \Rightarrow \theta=\cos^{-1}\left( \frac{8}{17} \right) \\  \\  \\ \tan\theta= \frac{opposite}{adjacent} = \frac{30}{16} = \frac{15}{8}  \\  \\ \Rightarrow \theta=\cos^{-1}\left( \frac{15}{8} \right)
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3 years ago
Without graphing or solving, determine the number of solutions of the system.
maw [93]

Answer:

Step-by-step explanation:

2)infinetly many solutions

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3 years ago
Find the area of the shaded region .
Greeley [361]

Calculate area of the white region inside circle.

Area of the two white triangles in top left and bottom right:

2 \cdot \frac{1}{2}(6)(6) = 36 ft^2

Area of the two white quarter circles in the bottom left and top right:

2 \cdot \frac{1}{4}\pi (6)^2 = 18\pi ft^2

Total area of unshaded white region inside circle:

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Area of entire circle including the white and shaded regions

\pi(6)^2 = 36\pi ft^2

Area of shaded region is area of entire circle - area of unshaded white region

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x° =125° y°= 125°

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Answer:

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Step-by-step explanation:

4 0
2 years ago
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