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3 years ago

How to solve the problem and the answer plz.

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

3 0

Answer:

x° =125° y°= 125°

Step-by-step explanation:

55° + x° = 180° because they are complementry angles

solve for x by subtracting 55° from both sides

x° = 125°

x° and y° is equal because they are vertical angles

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Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

7 0

3 years ago

I really extremely need help! I will give you 5 stars and branilest

Ivanshal [37]

Answer:

37.5%

Step-by-step explanation:

12\32 = 6\16=3\8 =0.375

=37.5%

7 0

2 years ago

A train leaves the station and has to travel 486km. The train maintains a speed of 120km. After travelling for 3 hours and 15 mi

Anuta_ua [19.1K]

Answer:

I think its 2 hours 30 minutes

Step-by-step explanation:

7 0

3 years ago

Plz help i really do need help

Maslowich

Answer:

it just says PDF won't let me download I. sorry

6 0

3 years ago

Can I have help on this

Alekssandra [29.7K]

Answer:

5.5

Step-by-step explanation:

22/4=5.5

can you please mark me as brainliest? thanks!

hope this helps!

5 0

3 years ago