Steady sounds like the best answer but that’s tough
Answer:
# Code in Python
dictionary={'A':1,'B':2,'C':3,'D':4}
other_dictionary={}
for keys in dictionary:
if dictionary[keys]&1==1:
temp=dictionary[keys]*dictionary[keys]-10*10
other_dictionary[keys]=temp
else:
other_dictionary[keys]=dictionary[keys]
print(other_dictionary)
assert other_dictionary
Explanation:
- Initialize a sample example dictionary and other_dictionary.
- Do a binary comparision for checking odd number
.
- Update the the value stored in the dictionary to store the squared difference of the original value and '10'.
- For even: store the original value (from dictionary).
Answer:
The affiliation of the writer is that She is on the staff at the Center for Food Safety (CFS).
Explanation:
CFS stands for the Center for Food Safety which is the national non-profitable public environmental and interest advocacy organization that is working for protect the human health and environment by the curbing use of the harmful food productions technologies and by the promoting an organic and other form of the sustainable agriculture.
Answer:
The answer is "Option A"
Explanation:
In the given java code, a class "Test" is defined, inside the main method try and catch block is used, inside the try block method "p()" is called, that print a message. in this block two catch block is used, that works on "NumberFormatException" and "RuntimeException". In the method "p" declaration, a string variable "s" is defined, that holds double value, that is "5.6", and converts its value into the wrong integer, and other wrong option can be described as follows:
- In option B, it is wrong, it is not followed by after call method.
- In option C, It is not followed by runtime exception, that's why it is incorrect.
- Option D and Option E both were wrong because they can't give run time and compile-time error.
